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Step-by-step intro to two-step linear equations

8.EE.A.1

Using exponents to describe numbers

Expanded powers

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Exponent rules

Single Power Expressions

Dividing powers

Multiplying powers

Order of operations with exponents

Product rule of exponents

Quotient rule of exponents

Power of a product rule

Power of a quotient rule

Power of a power rule

Simplify the power

8.EE.A.2

Squares and square roots

Square Root of a Perfect Square

Square and square roots

Cubic and cube roots

Cube root of a perfect cube

Converting radicals to mixed radicals

Converting radicals to entire radicals

8.EE.A.3

Scientific notation

8.EE.B.5

Parallel and perpendicular lines in linear functions

Understanding graphs of linear relationships

Linear relations

Understanding tables of values of linear relationships

Linear relation

Applications of linear relationships

Identifying proportional relationships

8.EE.B.6

Slope equation: $m = \frac{y_2-y_1}{x_2- x_1}$

Slope equation: <katex>m = \frac{y_2-y_1}{x_2- x_1}</katex>

Slope intercept form:  y = mx + b

Slope intercept form: y = mx + b

8.EE.C.7

Introduction to linear equations

Model and solve one-step linear equations: ax = b, x/a = b

One-step Linear Equations

One Step Linear Equations — Word Problem

One-step equations

One-step Equations LHS

One-step Equations RHS

Model And Solve One Step Linear Equations Divide – Word Problem

Model And Solve One Step Linear Equations Multiply – Word Problem

Solving two-step linear equations using addition and subtraction: ax + b = c

Two-step Linear Equations

Two-step Linear Equations LHS

Solve Linear Equations Using Addition and Subtraction – Word Problem

Two-step Linear Equations — Word Problem

Solving two-step linear equations using multiplication and division: x/a + b = c

Two-step Linear Equations RHS

Solving two-step linear equations using distributive property: a(x + b) = c

Solve Linear Equations Using Distributive Property – Word Problem

Solving literal equations

8.EE.C.8

Determining number of solutions to linear equations

Solving systems of linear equations by graphing

Solving systems of linear equations by elimination

Solving systems of linear equations by substitution

8.F.A.1

Relationship between two variables

Identifying functions

8.F.A.2

Function notation

8.F.B.4

Applications of linear relations

8.F.B.5

Graphing linear functions using table of values

8.G.A.1

Line symmetry

Tessellations using translations and reflections

tessellations using translations and reflections

8.G.A.2

Rotational symmetry and transformations

8.G.A.3

Enlargements and reductions with scale factors

Tessellations using rotations

8.G.A.4

Similar polygons

8.G.A.5

Similar triangles

8.G.B.6

Pythagorean theorem

Pythagorean Theorem

8.G.B.7

Using the pythagorean relationship

8.G.B.8

Distance formula: $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance formula: <katex>d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}</katex>

Distance formula

Applications of pythagorean theorem

8.G.C.9

Volume of cylinders

Word problems relating volume of prisms and cylinders

Surface area and volume of cones

Surface area and volume of spheres

8.NS.A.1

Understanding the number systems

Rational vs. Irrational numbers

8.NS.A.2

Determine square roots of rational numbers

Square roots of rational numbers

Estimating square roots

Converting repeating decimals to fractions

8.SP.A.1

Reading linear relation graphs

Box-and-whisker plots and scatter plots

8.SP.A.2

Solving linear equations by graphing

8th Grade Math

sample

math

Aquarium word problem: finding the original admission fee

Solving 2x + 4 = 8 using balance tiles and algebra

Solving 17 = 3x - 4 using algebra tiles and equations

<p>- Hi, and welcome to this question right here. So, we're going to do it by algebra tiles, okay? So, we know that the longer size one, when they're shaded in, you get yourself 3x, right? That's actually is 4x, I'm sorry. Okay, quickly correct that. That's 4x in total. Now, there's another three little boxes that are shaded in, they're for plus three. Now, this is going to equal to the other side, so what do we have over here? That's five times three, 15 empty little boxes. So you get yourselves negative one-five on the other side, okay? So, once you get the equation done you have to solve the x. So, 4x, here's the x, you have to move the three to the other side, okay? How do you do that? Well, simply minus three, you know it's simple math. Subtract the three from both sides. That's canceled. Negative 15 minus another three, think that if you owe men $15 you owe me another $3, so in total you owe me $18 in total, okay? Now, to solve the final x, I would recommend that, you know, just divide by four. You do it whatever you like, but if you're going to do it in a traditional way, just divide it by four to the bottom on both sides of the equation, that way you get the x equals to all by itself then negative 18 divided by four. I don't think that goes into perfectly anymore, so let's do a calculator, get a decimals out from here. We&apos;ve got 4.5, negative 4.5. And that's it. That is your final answer for this question. Thanks for watching.</p>

Solving 4x + 3 = -15 using tiles and algebra

Solving 9 = 5x - 6 using algebra tiles and equations

Solving 7x + 9 = 21 by subtracting then dividing

Solving a two-step equation with a leading constant: 98 - 2x = 14

Solving a two-step equation with x on the right side

Solving -4x - 11 = 109 using addition then division

In this section, we will look at linear equation questions which involve two kinds of operations: addition and subtraction. We will deal with two-step linear equations modeled by diagrams as a start. Then, we will learn how to solve algebraic equations and related word problems.

Solving two-step linear equations using addition and subtraction: <i>ax + b = c</i>