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Master Two-Step Equations with Distributive Property

8.EE.A.1

Using exponents to describe numbers

Expanded powers

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Exponent rules

Single Power Expressions

Dividing powers

Multiplying powers

Order of operations with exponents

Product rule of exponents

Quotient rule of exponents

Power of a product rule

Power of a quotient rule

Power of a power rule

Simplify the power

8.EE.A.2

Squares and square roots

Square Root of a Perfect Square

Square and square roots

Cubic and cube roots

Cube root of a perfect cube

Converting radicals to mixed radicals

Converting radicals to entire radicals

8.EE.A.3

Scientific notation

8.EE.B.5

Parallel and perpendicular lines in linear functions

Understanding graphs of linear relationships

Linear relations

Understanding tables of values of linear relationships

Linear relation

Applications of linear relationships

Identifying proportional relationships

8.EE.B.6

Slope equation: \(m = \frac{y_2-y_1}{x_2- x_1}\)

Slope equation: <katex>m = \frac{y_2-y_1}{x_2- x_1}</katex>

Slope intercept form:  y = mx + b

Slope intercept form: y = mx + b

8.EE.C.7

Introduction to linear equations

Model and solve one-step linear equations: ax = b, x/a = b

One-step Linear Equations

One Step Linear Equations — Word Problem

One-step equations

One-step Equations LHS

One-step Equations RHS

Model And Solve One Step Linear Equations Divide – Word Problem

Model And Solve One Step Linear Equations Multiply – Word Problem

Solving two-step linear equations using addition and subtraction: ax + b = c

Two-step Linear Equations

Two-step Linear Equations LHS

Solve Linear Equations Using Addition and Subtraction – Word Problem

Two-step Linear Equations — Word Problem

Solving two-step linear equations using multiplication and division: x/a + b = c

Two-step Linear Equations RHS

Solving two-step linear equations using distributive property: a(x + b) = c

Solve Linear Equations Using Distributive Property – Word Problem

Solving literal equations

8.EE.C.8

Determining number of solutions to linear equations

Solving systems of linear equations by graphing

Solving systems of linear equations by elimination

Solving systems of linear equations by substitution

8.F.A.1

Relationship between two variables

Identifying functions

8.F.A.2

Function notation

8.F.B.4

Applications of linear relations

8.F.B.5

Graphing linear functions using table of values

8.G.A.1

Line symmetry

Tessellations using translations and reflections

tessellations using translations and reflections

8.G.A.2

Rotational symmetry and transformations

8.G.A.3

Enlargements and reductions with scale factors

Tessellations using rotations

8.G.A.4

Similar polygons

8.G.A.5

Similar triangles

8.G.B.6

Pythagorean theorem

Pythagorean Theorem

8.G.B.7

Using the pythagorean relationship

8.G.B.8

Distance formula: \(d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)

Distance formula: <katex>d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}</katex>

Distance formula

Applications of pythagorean theorem

8.G.C.9

Volume of cylinders

Word problems relating volume of prisms and cylinders

Surface area and volume of cones

Surface area and volume of spheres

8.NS.A.1

Understanding the number systems

Rational vs. Irrational numbers

8.NS.A.2

Determine square roots of rational numbers

Square roots of rational numbers

Estimating square roots

Converting repeating decimals to fractions

8.SP.A.1

Reading linear relation graphs

Box-and-whisker plots and scatter plots

8.SP.A.2

Solving linear equations by graphing

8th Grade Math

sample

math

Intro

Ex. 1:

Ex. 2:

Ex. 3:

Solving 4(x + 1) = 12 using algebra tile models

- Hi and welcome to this question right here. So we&apos;ve got another expression right here and we're going to create a model. To save a little bit of time, I actually did a drawing already. So it's two sets of X minus three and once again, the X in the algebra tiles is a longer piece. It is shaded in because it's positive. The minus three is represented by the empty boxes over here. So we&apos;ve got X minus three. We&apos;ve got one set and two sets because of the two in the front. Then it's equal to there's eight boxes over here, shaded in, right? 
So it represents positive eight. How do we solve the X in this case? Well by using the diagram. Well, we're still going to do it just like algebraically. What happened is we have to move these boxes here first, okay? So that means I'm going to take all of them and I'm going to move them to the other side. What happened is this is actually negative six. If you bring it over, it becomes positive six. So I'm going to grab my red pen right here, right now and I'm going to add a positive six to this side right now. Pretend that you take this guy right here, our negative six. You bring it over, they become positive six. So I'm going to add a one and two and three and four and five and six. Now after I've moved it over, what happened is these guys over here now disappeared, okay? So they are now do not belong to the question anymore. Now I got a X, 2X on this side, and you got 14 on this side. So we're trying to figure out what X equals to, right? Well here we go. We&apos;ve got two sets on each side right now, okay? So what you do is you grab your pen or pencil and just kind of put them all together like that, okay? So that kind of tells you that in each set, see that X right there in the first one? That X equals to... I'll just write the answer down here. 1, 2, 3, 4, 5, 6, 7. It's equal to positive seven and that's the answer for this question. So X equal to seven. If you're not quite sure, plug it back into the equation. Seven minus three is four. Four times two is eight. You get the same answer to the left and the right. This is your answer for this question. Thanks for watching.

Solving 2(x - 3) = 8 using algebra tiles model

Solving 7(10 + x) = 14 using distribution and inverse operations

Solving -15 = 3(x - 6) using distributive property

Solving 11(x + 13) = -22 using distribution and inverse operations

Writing a circumference equation for a resized round table

Solving 3(x - 9) = 45 using distributive property

Solving for the new radius and calculating the table's circumference

Intro to solving equations using the distributive property

Distributive property is an algebra property that we use all the time! When you see equations in the form of a(x+b), you can transform them into ax+ab by multiplying the terms inside a set of parentheses. In this section, we will make use of this property to help us solve linear equations.

Solving two-step linear equations using distributive property: a(x + b) = c

Solving linear equations using distributive property: a(x + b) = c

Solving two-step linear equations using distributive property: a(x+b)=c

Distributive property &mdash; two-step linear equations

Model and solve one-step linear equations: ax = b, x/a = b

Solving two-step linear equations using addition and subtraction: ax + b = c

Solving two-step linear equations using multiplication and division: x/a + b = c