A standard die has 6 faces, numbered 1 through 6, so there are 6 total outcomes. Suppose event \(A\) is rolling a number greater than 4. The favorable outcomes are 5 and 6, so there are 2 favorable outcomes.
\( P(A) = \dfrac{2}{6} = \dfrac{1}{3} \)
So the probability of rolling a number greater than 4 is \( \dfrac{1}{3} \), or about 33 percent. This kind of single-trial calculation is exactly what you practice in simple probability experiments, where you count outcomes from a spinner, coin, or die.