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Master the Pythagorean Theorem: Examples and Applications

CA.G.G.C.1

Central angles and proofs

CA.G.G.C.2

Inscribed angles and proofs

CA.G.G.C.3

Circle chord, tangent, and inscribed angles proofs

CA.G.G.C.5

auto-gen

Converting between degrees and radians

Trigonometric ratios of angles in radians

Radian measure and arc length

Arcs of a circle

Areas and sectors of circles

CA.G.G.CO.1

Central and inscribed angles in circles

Parallel and perpendicular line segments

Identifying Parallel Lines

Identifying Perpendicular Lines

CA.G.G.CO.10

Isosceles and equilateral triangles

CA.G.G.CO.2

Rotational symmetry and transformations

Scale diagrams

Similar polygons

Introduction to transformations

CA.G.G.CO.4

Line symmetry

Perpendicular line proofs

CA.G.G.CO.6

Classifying triangles

Congruence and congruent triangles

CA.G.G.CO.8

Triangles congruent by SSS proofs

Triangles congruent by SAS and HL proofs

Triangles congruent by ASA and AAS proofs

CA.G.G.CO.9

Pairs of lines and angles

Parallel lines and transversals

Parallel line proofs

CA.G.G.GMD.1

Circles and circumference

Circle properties

Surface area and volume of cylinders

Surface area and volume of cones

CA.G.G.GMD.3

Surface area and volume of pyramids

Surface area and volume of spheres

CA.G.G.GMD.4

Surface area and volume of prisms

CA.G.G.GPE.1

Conics - Circle

CA.G.G.GPE.2

Conics - Parabola

CA.G.G.GPE.4

Distance formula: \(d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)

Distance formula: <katex>d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}</katex>

Distance formula

Slope equation: \(m = \frac{y_2-y_1}{x_2- x_1}\)

Slope equation: <katex>m = \frac{y_2-y_1}{x_2- x_1}</katex>

Slope intercept form:  y = mx + b

Slope intercept form: y = mx + b

General form:  Ax  + By  + C = 0

General form: Ax + By + C = 0

CA.G.G.GPE.5

Parallel line equation

Perpendicular line equation

Combination of both parallel and perpendicular line equations

Parallel and perpendicular lines in linear functions

CA.G.G.GPE.6

Midpoint formula: \(M = ( \frac{x_1+x_2}2  ,\frac{y_1+y_2}2)\)

Midpoint formula

Midpoint formula: <katex>M = ( \frac{x_1+x_2}2  ,\frac{y_1+y_2}2)</katex>

Midpoint formula: <katex>M = ( \frac{x_1+x_2}2 ,\frac{y_1+y_2}2)</katex>

CA.G.G.MG.3

Word problems of polynomials

CA.G.G.S.CP.1

Organizing outcomes

Calculating Outcomes

CA.G.G.S.CP.2

Probability of independent events

CA.G.G.S.MD.6

Introduction to probability

Identify the Probability — Word Problem

Compound Probability

Reading Probability Models

Probability

CA.G.G.S.MD.7

Comparing experimental and theoretical probability

comparing experimental and theoretical probability

CA.G.G.SRT.1

Enlargements and reductions with scale factors

CA.G.G.SRT.10

Law of sines

Ambiguous case: SSA triangles

Law of cosines

CA.G.G.SRT.11

Applications of the sine law and cosine law

CA.G.G.SRT.2

Similar triangles

CA.G.G.SRT.4

Pythagorean theorem

Pythagorean Theorem

Estimating square roots

Using the pythagorean relationship

Applications of pythagorean theorem

CA.G.G.SRT.6

Use sine ratio to calculate angles and sides (Sin = o / h)

Use tangent ratio to calculate angles and sides (Tan = o / a)

CA.G.G.SRT.7

Quotient identities and reciprocal identities

Pythagorean identities

Sum and difference identities

Sum and Difference Identities

Double-angle identities

Use cosine ratio to calculate angles and sides (Cos = a / h)

Cofunction identities

CA.G.G.SRT.8

Combination of SohCahToa questions

Word problems relating ladder in trigonometry

Word problems relating guy wire in trigonometry

CA.G.G.SRT.8.1

Solving expressions using 45-45-90 special right triangles

Solving expressions using 30-60-90 special right triangles

CA.G.G.SRT.9

Area of triangles: 1/2 a*b sin(C)

math

Intro

<p>- Hi and welcome to this question right here. We're trying to find the side lengths of the squares. So as you can see we&apos;ve got 1, 2, 3 different squares right here and with a right triangle in the middle. This square here we already know all the sides. It's 18, 18, 18, 18. Where as this one here is 24, 24, 24, 24. Now we're probably trying to figure out this one over here. If you can figure out this one then that means you figured out all the side length of this big rectangle...sorry, square. The only hint that we have is that this is a 90 degrees. So if you have a 90 degrees that means you can go ahead and use a Pythagoras which is C squared equals A squared plus the B squared and that's the formula you want to memorize. So what happened is the C is always the hypotenuse, the longest side of the right triangle. So we're going to call this one C right here. We don't know what the C is. We're going to square the whole thing to solve for C. Remember you had to square root both sides so they can solve the C. For A and B it's your choice. You can choose whatever you like. You get the 18 and 24. So A and B are just two lengths of that right triangle. So you can punch in 18 for the A and the 24 for the B. So what happens at the end, you go 18 square. We have 324 for this number and 24 squared for 576. And you square root the whole thing. Make sure you add them before you square, though. 324 plus 576. I got a 900. So to show you all the work. So square root of that we&apos;ve got ourselves just 30, okay? So that means this C over here, this hypotenuse of this triangle, is going to be a 30 centimeter and that is the side of this square over here and that's what they're looking for. So your answer is just 30 centimeter. Thanks for watching.</p>

In the nutshell, Pythagorean theorem/Pythagorean relationship describes the relationship between the lengths and sides of a right triangle. After thousands of repeated examinations by the ancient Greek mathematicians, it was found that the square of the hypotenuse is equal to the sum of the squares of the other two sides c&sup2; = a&sup2; + b&sup2;. 

Introduction to pythagorean theorem

Examples of the pythagorean theorem

Introduction to Exponents

Classifying Triangles