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Master Square Root Estimation: Quick & Accurate Techniques

CA.G.G.C.1

Central angles and proofs

CA.G.G.C.2

Inscribed angles and proofs

CA.G.G.C.3

Circle chord, tangent, and inscribed angles proofs

CA.G.G.C.5

auto-gen

Converting between degrees and radians

Trigonometric ratios of angles in radians

Radian measure and arc length

Arcs of a circle

Areas and sectors of circles

CA.G.G.CO.1

Central and inscribed angles in circles

Parallel and perpendicular line segments

Identifying Parallel Lines

Identifying Perpendicular Lines

CA.G.G.CO.10

Isosceles and equilateral triangles

CA.G.G.CO.2

Rotational symmetry and transformations

Scale diagrams

Similar polygons

Introduction to transformations

CA.G.G.CO.4

Line symmetry

Perpendicular line proofs

CA.G.G.CO.6

Classifying triangles

Congruence and congruent triangles

CA.G.G.CO.8

Triangles congruent by SSS proofs

Triangles congruent by SAS and HL proofs

Triangles congruent by ASA and AAS proofs

CA.G.G.CO.9

Pairs of lines and angles

Parallel lines and transversals

Parallel line proofs

CA.G.G.GMD.1

Circles and circumference

Circle properties

Surface area and volume of cylinders

Surface area and volume of cones

CA.G.G.GMD.3

Surface area and volume of pyramids

Surface area and volume of spheres

CA.G.G.GMD.4

Surface area and volume of prisms

CA.G.G.GPE.1

Conics - Circle

CA.G.G.GPE.2

Conics - Parabola

CA.G.G.GPE.4

Distance formula: \(d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)

Distance formula: <katex>d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}</katex>

Distance formula

Slope equation: \(m = \frac{y_2-y_1}{x_2- x_1}\)

Slope equation: <katex>m = \frac{y_2-y_1}{x_2- x_1}</katex>

Slope intercept form:  y = mx + b

Slope intercept form: y = mx + b

General form:  Ax  + By  + C = 0

General form: Ax + By + C = 0

CA.G.G.GPE.5

Parallel line equation

Perpendicular line equation

Combination of both parallel and perpendicular line equations

Parallel and perpendicular lines in linear functions

CA.G.G.GPE.6

Midpoint formula: \(M = ( \frac{x_1+x_2}2  ,\frac{y_1+y_2}2)\)

Midpoint formula

Midpoint formula: <katex>M = ( \frac{x_1+x_2}2 ,\frac{y_1+y_2}2)</katex>

Midpoint formula: <katex>M = ( \frac{x_1+x_2}2 ,\frac{y_1+y_2}2)</katex>

CA.G.G.MG.3

Word problems of polynomials

CA.G.G.S.CP.1

Organizing outcomes

Calculating Outcomes

CA.G.G.S.CP.2

Probability of independent events

CA.G.G.S.MD.6

Introduction to probability

Identify the Probability — Word Problem

Compound Probability

Reading Probability Models

Probability

CA.G.G.S.MD.7

Comparing experimental and theoretical probability

comparing experimental and theoretical probability

CA.G.G.SRT.1

Enlargements and reductions with scale factors

CA.G.G.SRT.10

Law of sines

Ambiguous case: SSA triangles

Law of cosines

CA.G.G.SRT.11

Applications of the sine law and cosine law

CA.G.G.SRT.2

Similar triangles

CA.G.G.SRT.4

Pythagorean theorem

Pythagorean Theorem

Estimating square roots

Using the pythagorean relationship

Applications of pythagorean theorem

CA.G.G.SRT.6

Use sine ratio to calculate angles and sides (Sin = o / h)

Use tangent ratio to calculate angles and sides (Tan = o / a)

CA.G.G.SRT.7

Quotient identities and reciprocal identities

Pythagorean identities

Sum and difference identities

Sum and Difference Identities

Double-angle identities

Use cosine ratio to calculate angles and sides (Cos = a / h)

Cofunction identities

CA.G.G.SRT.8

Combination of SohCahToa questions

Word problems relating ladder in trigonometry

Word problems relating guy wire in trigonometry

CA.G.G.SRT.8.1

Solving expressions using 45-45-90 special right triangles

Solving expressions using 30-60-90 special right triangles

CA.G.G.SRT.9

Area of triangles: 1/2 a*b sin(C)

math

Intro

- [Instructor] Hi, welcome to this question right here. So we're trying to estimate what is root 66 manually, now without the calculator. So the work is actually pretty simple. You draw yourself a number line and you make yourself two lines right here to represent two numbers. Now these two numbers here is going to be enclosing the 66 but they have to be perfect square numbers. For example, 64 is... that's the first number that come to me because 66 is greater than 64, right? Sixty-four turns out to be and eight square which is a perfect square number. So I know the root 66 is definitely greater than eight but eight point something, something which I don't know yet. Then this number over here is going to be... after eight there's a nine, nine times nine is 81. So this is 81 right here. So I know this root 66 is definitely between 8 and the 9. But where is it? 
Well, we can actually calculate it approximately, estimation. Take the 81 right here and subtract to 64. There's 17 units across from 64 to 81. 17, so I'm not going to do all of them though. I'm just going to cut it in half. So this will be 8.5, and if there's 17 units. 17 divided by 2 I get 8.5 units. So 64 + 8.5, I got myself-- This is actually my 72.5, on the number line, but in terms of the square root of this number. Let me put square numbers on these guys right here. It will be 8.5, just perfectly halfway. Now, the 66 is actually between these two guys right here, but are they closer to the half or they're closer to the 8? 
Well, if I just take my 72.5 over here and subtract the 64, I have 8.5 units. So this one is actually not that bad. I can actually do 8.5, then I go-- That's halfway, that's 1, 2, 3, 4 5, 6, 7, 8 and a half maybe. This is approximation, so don't be too serious about these guys. Approximately 8.5 units. Okay, then I think-- Every unit is a one now, so that's 66 right? This is 64, 65, 66 is right here. This is my 66, okay? So that's root 64, root 65, root 66. So as you can see, it's very, very close to my 8. See, this is 8 right here. This is 8.5, so if you just quickly do a quick approximation. It will be 8.1, 8.2, 8.3 and 8.4. If I just quickly draw a lines approximately because I don't, I didn't really do have a good scale on these guys. If you have like a grid paper, probably much easier. This is 8 right? 
Then this is like 8.1, 8.2, 8.3, 8.4, 8.5. So it looks like I'm just a little bit on the 8.1 something. I'm going to do an approximation, 8.1. That's pretty much it, 8.10. That's what I'm going to put down. Approximately estimated, it's going to be my 8.10. Now, if I punch it in a calculator, radical of 66 then I got myself-- I'm pretty close actually. It's going to be 8.12, but once again I don't have a good scales right here. If you draw them perfectly with the equal distance, if you draw the units perfectly, you will get a better approximation than this. But that's the work, and once again find your perfect score numbers that will enclose that number 66, and then just draw, figure out how many units between them, figure out how many units between them, then just slowly figure out where your location is and just do the approximation. Thanks for watching.

To estimate square roots which are not perfect squares without using a calculator, we need to know the perfect square numbers well. We will first put the number inside the square root sign in the middle of a number line, and then find the two closest perfect square numbers on its left and right hand side to make the best estimation.

How do you estimate the value of square roots?

Divisibility rules

Introduction to Exponents