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Mastering Pythagorean Theorem Applications in Real Life

CA.G.G.C.1

Central angles and proofs

CA.G.G.C.2

Inscribed angles and proofs

CA.G.G.C.3

Circle chord, tangent, and inscribed angles proofs

CA.G.G.C.5

auto-gen

Converting between degrees and radians

Trigonometric ratios of angles in radians

Radian measure and arc length

Arcs of a circle

Areas and sectors of circles

CA.G.G.CO.1

Central and inscribed angles in circles

Parallel and perpendicular line segments

Identifying Parallel Lines

Identifying Perpendicular Lines

CA.G.G.CO.10

Isosceles and equilateral triangles

CA.G.G.CO.2

Rotational symmetry and transformations

Scale diagrams

Similar polygons

Introduction to transformations

CA.G.G.CO.4

Line symmetry

Perpendicular line proofs

CA.G.G.CO.6

Classifying triangles

Congruence and congruent triangles

CA.G.G.CO.8

Triangles congruent by SSS proofs

Triangles congruent by SAS and HL proofs

Triangles congruent by ASA and AAS proofs

CA.G.G.CO.9

Pairs of lines and angles

Parallel lines and transversals

Parallel line proofs

CA.G.G.GMD.1

Circles and circumference

Circle properties

Surface area and volume of cylinders

Surface area and volume of cones

CA.G.G.GMD.3

Surface area and volume of pyramids

Surface area and volume of spheres

CA.G.G.GMD.4

Surface area and volume of prisms

CA.G.G.GPE.1

Conics - Circle

CA.G.G.GPE.2

Conics - Parabola

CA.G.G.GPE.4

Distance formula: \(d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)

Distance formula: <katex>d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}</katex>

Distance formula

Slope equation: \(m = \frac{y_2-y_1}{x_2- x_1}\)

Slope equation: <katex>m = \frac{y_2-y_1}{x_2- x_1}</katex>

Slope intercept form:  y = mx + b

Slope intercept form: y = mx + b

General form:  Ax  + By  + C = 0

General form: Ax + By + C = 0

CA.G.G.GPE.5

Parallel line equation

Perpendicular line equation

Combination of both parallel and perpendicular line equations

Parallel and perpendicular lines in linear functions

CA.G.G.GPE.6

Midpoint formula: \(M = ( \frac{x_1+x_2}2  ,\frac{y_1+y_2}2)\)

Midpoint formula

Midpoint formula: <katex>M = ( \frac{x_1+x_2}2 ,\frac{y_1+y_2}2)</katex>

Midpoint formula: <katex>M = ( \frac{x_1+x_2}2 ,\frac{y_1+y_2}2)</katex>

CA.G.G.MG.3

Word problems of polynomials

CA.G.G.S.CP.1

Organizing outcomes

Calculating Outcomes

CA.G.G.S.CP.2

Probability of independent events

CA.G.G.S.MD.6

Introduction to probability

Identify the Probability — Word Problem

Compound Probability

Reading Probability Models

Probability

CA.G.G.S.MD.7

Comparing experimental and theoretical probability

comparing experimental and theoretical probability

CA.G.G.SRT.1

Enlargements and reductions with scale factors

CA.G.G.SRT.10

Law of sines

Ambiguous case: SSA triangles

Law of cosines

CA.G.G.SRT.11

Applications of the sine law and cosine law

CA.G.G.SRT.2

Similar triangles

CA.G.G.SRT.4

Pythagorean theorem

Pythagorean Theorem

Estimating square roots

Using the pythagorean relationship

Applications of pythagorean theorem

CA.G.G.SRT.6

Use sine ratio to calculate angles and sides (Sin = o / h)

Use tangent ratio to calculate angles and sides (Tan = o / a)

CA.G.G.SRT.7

Quotient identities and reciprocal identities

Pythagorean identities

Sum and difference identities

Sum and Difference Identities

Double-angle identities

Use cosine ratio to calculate angles and sides (Cos = a / h)

Cofunction identities

CA.G.G.SRT.8

Combination of SohCahToa questions

Word problems relating ladder in trigonometry

Word problems relating guy wire in trigonometry

CA.G.G.SRT.8.1

Solving expressions using 45-45-90 special right triangles

Solving expressions using 30-60-90 special right triangles

CA.G.G.SRT.9

Area of triangles: 1/2 a*b sin(C)

math

Intro

Hi, welcome to this question right here. So we&apos;ve got a plane, kinda flew from a point A starting from here, it went to the point B for 300 meters, then for some reason a 90&deg; turn and went to a point C for another 400 meters, okay. And we're trying to figure out how far is a plane from point A which means you're now here, we're looking for how far are you, from where you start, okay? 
So that's the side right there, and as you can see, that's a right triangle, okay? 
So it looks like you're missing the X over here which is the hypotenuse. So Pythagorean theorem, here it comes one more time. So C&sup2; = a&sup2; + b&sup2;, 
and once again the hypotenuse is always the longest side of the right triangle. So you have to put your X&sup2; here, but for A and B it's your choice, you can put your a for this one or this one, b for this one or that, it doesn't matter so let's just plug it in 300 and square that plus the 400 and square that. Now I'm just gonna find out the answer on the right hand side. Squaring the both sides and adding them together we get ourselves the 250,000, and my X square is still missing. So to figure out the X, I will square root both sides. Why do I do that? 
Because it allows me to cancel the square sign right there. So I end up with just the X and I just have to square root my 250,000 then I get myself the 500 and it looks like it's meter, and that's the answer for this question. Thanks for watching.

We will need to apply Pythagorean Theorem often in our daily life. In this lesson, we will focus on tackling some Pythagorean Theorem word problems. 

Word problems of pythagorean relationship

Applying the Pythagorean Theorem