Electric potential and electric potential energy

Everything You Need in One Place

Homework problems? Exam preparation? Trying to grasp a concept or just brushing up the basics? Our extensive help & practice library have got you covered.

Learn and Practice With Ease

Our proven video lessons ease you through problems quickly, and you get tonnes of friendly practice on questions that trip students up on tests and finals.

Instant and Unlimited Help

Our personalized learning platform enables you to instantly find the exact walkthrough to your specific type of question. Activate unlimited help now!

0/4
?
Examples
Lessons
  1. Electric potential energy and electric potential between parallel plates (constant E)
    There is a constant electric field of 11 500 N/C between a pair of oppositely-charged parallel plates spaced 0.0475 m apart.
    1. Find the amount of work needed to move a proton from the surface of the negative plate to the surface of the positive plate, and how much electric potential energy the proton has gained after it is moved.
    2. If a proton is held at the positive plate surface and released, find the speed of the proton when it reaches the surface of the negative plate.
    3. Find the electric potential difference between the two plates. What potential energy would a 6.00×107C6.00 \times 10^{-7} C charge have at the positive plate surface?
  2. Electric potential energy and electric potential of a point charge (non-constant E)
    Find the electric potential at each point A and B, and the potential difference between A and B. If 0.060 J of work must be done on a charge to move it from A to B, find the magnitude and polarity of the charge.
    Topic Notes
    ?
    In this lesson, we will learn:
    • The meaning of electric potential and electric potential energy
    • How to understand electric potential energy problems by analogy to gravitation problems
    Notes:

    • Electric potential energy (Ep) is the energy stored in a charge due to its location in an electric field. For example, moving two like charges close together stores potential energy, since the charges repel each other. Separating opposite charges also stores potential energy, since the charges attract each other. It is similar idea to gravitational potential energy.
    • It is useful to calculate changes in electric potential energy using the concept of electric potential difference (ΔV\Delta V). An electric potential (VV) is the electric potential energy of a charge q, divided by q. ΔV\Delta V is the difference in VV between two points.

    Electric Potential Energy (Two Point Charges)

    Ep=kQ1Q2r2E_p = k \frac{Q_1 Q_2}{r^2}
    Ep:E_p: electric potential energy, in joules (J)
    k=9.00×109Nm2/C2k = 9.00 \times 10^9 N\centerdot m^2 / C^2 (Coulomb's constant)
    Q1,Q2:Q_1, Q_2: charge on each body, in coulombs (C)
    r:r: distance between charges, in meters (m)

    Electric Potential Energy (Charge in Constant Electric Field)

    Ep=qEdE_p=qEd
    EE: electric field, in newtons per coulomb (N/C)
    qq: charge that experiences the EE, in coulombs (C)
    dd: distance from location chosen as Ep=0E_p=0 J, meters (m)

    Electric Potential

    V=EpqV=\frac{E_p}{q}
    VV: electric potential, in volts (V)
    EpE_p: electric potential energy, in newtons (N)
    qq: charge that experiences the potential, in coulombs (C)

    Electric Potential Difference

    ΔV=VfVi=Won  qq=ΔEqq\Delta V=V_f - V_i = \frac{W_{on\;q}}{q} = \frac{\Delta E_q}{q}
    ΔV\Delta V: electric potential difference, in volts (V)
    Vi,VfV_i,V_f: electric potential at initial and final points, in volts (V)
    qq: charge that experiences the potential, in coulombs (C)
    Won  qW_{on\;q}: work to move qq from the initial point to the final point, in joules (J)
    ΔEq\Delta E_q: change in potential energy of qq between the initial and final points, in joules (J)

    Useful Constants

    k=9.00×109Nm2/C2k = 9.00 \times 10^9 N\centerdot m^2 / C^2 (Coulomb's constant)
    e=1.60×1019Ce = 1.60 \times 10^{-19} C (Elementary charge. qproton=e,qelectron=eq_{proton}=e, q_{electron}=-e)
    mproton=1.67×1027m_{proton}=1.67 \times 10^{-27} kg
    melectron=9.11×1031m_{electron}=9.11 \times 10^{-31} kg