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Solving polynomials with the unknown "c" from x^2 + bx + c

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Finding the Unknown c in x² + bx + c

When a quadratic trinomial x squared plus bx plus c factors as (x+p)(x+q), the constant c equals the product of p and q. Learn to find the missing c from a factored form or known roots, and how it connects to finding the missing b.

Finding the unknown c in x² + bx + c

A quadratic trinomial in the form x² + bx + c factors as (x + p)(x + q) when two numbers p and q multiply to give c and add to give b. If you're given the factored form, or the two numbers p and q, finding c is just one multiplication: c = p × q.

Finding c in x²+bx+c Given the factored form (x+2)(x+5), the constant c in x squared plus bx plus c equals the product of 2 and 5, which is 10. Factored form: (x + 2)(x + 5) c = product of constants:c = 2 × 5 = 10 b = sum of constants:b = 2 + 5 = 7 x² + 7x + 10 = (x + 2)(x + 5)
From the factored form (x+2)(x+5), c is the product of the constants: 2 × 5 = 10.

Worked example

Given the factored form (x + 2)(x + 5), find c in x² + bx + c. The constant term comes from multiplying the two numbers: c = 2 × 5 = 10. (The coefficient b comes from adding them: b = 2 + 5 = 7.) So x² + 7x + 10 = (x + 2)(x + 5).

Working backward from roots

If you're given the two roots of the equation instead of a factored expression, the same idea applies: c is still the product of the two root-related numbers. This mirrors factoring trinomials in reverse — instead of factoring x² + bx + c, you're building it from known factors.

Why this matters

This skill connects finding missing coefficients to the broader pattern used in finding the unknown b and general polynomial factoring: once you know a trinomial's factored form, both b and c follow directly from the two numbers inside the parentheses.

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