The argument of \(z = a + bi\) is the angle \(\theta\) measured from the positive real axis to the segment connecting the origin to the point \((a, b)\). Because \(a\), \(b\), and the modulus form a right triangle, the argument can be found using the tangent ratio:
\( \tan(\theta) = \dfrac{b}{a} \quad \Rightarrow \quad \theta = \tan^{-1}\left(\dfrac{b}{a}\right) \)
This formula alone only gives an angle between \(-90^\circ\) and \(90^\circ\), so you always need to check which quadrant the point \((a, b)\) lies in and adjust the angle accordingly. The principal argument is the value of \(\theta\) chosen so that \(-180^\circ < \theta \le 180^\circ\) (equivalently \(-\pi < \theta \le \pi\)).
Example 3: Argument of -1 + i
Here \(a = -1\) and \(b = 1\), which places the point in the second quadrant. The reference angle satisfies \(\tan(\theta) = \left|\dfrac{1}{-1}\right| = 1\), and this ratio matches the familiar 45-45-90 special right triangle, giving a reference angle of \(45^\circ\). Since the point is in the second quadrant, the principal argument is:
\( \theta = 180^\circ - 45^\circ = 135^\circ \)
The modulus of this number is \( |{-1} + i| = \sqrt{(-1)^2 + 1^2} = \sqrt{2} \), so \(-1 + i\) sits at distance \(\sqrt{2}\) from the origin, at an angle of \(135^\circ\).