Solve √(2x + 3) = x. The radical is already isolated. Squaring both sides gives 2x + 3 = x², which rearranges to x² − 2x − 3 = 0, factoring to (x−3)(x+1) = 0, giving x = 3 or x = −1.
Checking in the original equation: for x = 3, √9 = 3, which is true — keep it. For x = −1, √1 = 1, but 1 ≠ −1 — this solution is extraneous and must be rejected. The only valid solution is x = 3.
Radical equations often build on earlier radical skills, like multiplying and dividing radicals to simplify a term before isolating it, or recognizing the shape of a square root function in the equation.