TOPIC

Solving simultaneous linear equations by elimination

MY PROGRESS

Pug Score

0%

Best Streak

0 in a row

Study Points

+0

Overview

Practice

Watch

Read

Quiz

Next Steps


Get Started

Get unlimited access to all videos, practice problems, and study tools.

Unlimited practice
Full videos

Back to Menu

Topic Progress

Pug Score

0%

Videos Watched

0/0

Best Practice

No score

Read

Not viewed

Best Quiz

No attempts


Best Streak

0 in a row

Study Points

+0

Read

Solving Systems by Elimination

The elimination method solves a system of linear equations by adding or subtracting the equations so one variable cancels, leaving a single equation to solve. Learn how to line up terms, multiply to match coefficients, eliminate a variable, and back-substitute, with a worked example.

What the elimination method is

The elimination method solves a system of linear equations by adding or subtracting the equations so that one variable cancels, leaving a single equation in one variable to solve.

The steps

The elimination method, step by step Worked example. The system is 2x plus 3y equals 12 and 2x minus y equals 4. The x coefficients already match, so subtracting the second equation from the first eliminates x and gives 4y equals 8, so y equals 2. Back-substituting y equals 2 into the first equation gives x equals 3. 2x + 3y = 122x − y = 4 x-coefficients match → subtract to eliminate x 4y = 8 y = 2 Back-substitute y = 2 into 2x + 3y = 12: 2x + 6 = 12 x = 3
Elimination: match a variable's coefficients, subtract to cancel it, solve, then back-substitute.

Line up the equations, multiply one or both so a variable has matching coefficients, add or subtract to eliminate that variable, solve for what remains, then back-substitute to find the other variable.

Worked example

Solve 2x + 3y = 12 and 2x − y = 4. The x-coefficients already match, so subtracting gives 4y = 8, so y = 2. Substituting into the first equation gives 2x + 6 = 12, so x = 3. The solution is (3, 2).

Elimination vs substitution

Elimination is quickest when coefficients already line up; otherwise substitution may be easier. Either way, a system can have one solution, none, or infinitely many — see determining the number of solutions.

Related lessons