Induced EMF in a moving conductor
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- A 1.2m length of wire is pulled through a uniform 0.045 T magnetic field at 6.7m/s as shown. What emf is generated between the ends of the wire?
- 0V
- 0.090V
- 0.36V
- 0.45V
- A solid conductor travels at 150m/s across a uniform 0.045T magnetic field. Which side is positively charged and what is the emf across this block?
- The circular loop of wire shown below has an area of 0.40 m2 and is in a 0.60T magnetic field. This filed increased to 1.40 T in 0.25 s.
- A 0.050m long conducting wire is moved through a 1.5 T magnetic field as shown below.
What is the magnitude of the emf generated between its ends, and in what direction do the electrons in the conductor initially move? - A circular loop of resistance 1.2 Ω is pulled a distance of 0.40m into a perpendicular magnetic field as shown below.
an average current of 0.50A is produced in the coil during this event. Calculate the constant speed with which the coil was pulled.- 0.10 m/s
- 0.75 m/s
- 1.9 m/s
- 2.4 m/s
- A 0.75 m conducting rod is moved at 8.0m/s across a 0.25 T magnetic field along rails. The electrical resistance of the system is 5.0 Ω. What are the magnitude and direction through point X?
- A 200-turn coil has a 15.2 V potential difference induced in it when the magnetic field changes from 0.42 T to 0.22 T in the opposite direction in 3.2 ×10?2 s. What is the radius of this coil?
- 3.5 × 10?2m
- 5.1 × 10?2m
- 5.9 × 10?2m
- 6.2 × 10?2m
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Topic Notes
In this lesson, we will learn:
- Moving a conductor in a uniform magnetic field results in an induced emf across the conductor.
- How to find the magnitude of the electromotive force?
- How to find the direction of the electromotive force?
Notes:
- Moving a conductor in a uniform magnetic field results in an induced emf across the conductor.
- As the conductor moves, there is a change in magnetic flux, due to the change in area of the conductor that is exposed to the magnetic field lines.
- Change in flux results in electromotive force induction and induced emf in the loop.
- According to Faraday’s law:
l = length of the rod
B = magnetic field
v = speed of the rod
A = area of the loop
If the rod moves at speed of v, it travels a distance of Δx, in a time Δt;
Therefore, the area of the loop changes by an amount of ΔA = lΔx
- The direction of the induced current is in a way to oppose the change in flux.
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