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Still Confused?

Try reviewing these fundamentals first

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Try reviewing these fundamentals first

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Get Started Now- Lesson: 16:49
- Lesson: 27:21
- Lesson: 36:03

Basic Concepts: Solving systems of linear equations by elimination

Related Concepts: Solving 3 variable systems of equations by substitution, Solving 3 variable systems of equations with no or infinite solutions

The idea of elimination is to convert 3 equations with 3 variables to 2 equations with 2 variables, then to 1 equation with 1 variable.

- 1.
**Solving Three Variable Systems of Equations by Elimination – (Easy)**Solve the following system of equations by elimination:

$x - 4y + z = -12$

$x + 3y - z = 6$

$2x - 2y + z = 5$

- 2.
**Solving Three Variable Systems of Equations by Elimination – (Medium)**Solve the following system of equations by elimination:

$4x - 3y + 2z = 20$

$-2x - 4y + 3z = 3$

$x + y - z = 2$

- 3.
**Solving Three Variable Systems of Equations by Elimination – (Hard)**Solve the following system of equations by elimination:

$x + 4y + 7z = 109$

$4x - 5y + 4z = -29$

$5x + y - z = 10$

8.

Systems of Equations

8.1

System of linear equations

8.2

System of linear-quadratic equations

8.3

System of quadratic-quadratic equations

8.4

Solving 3 variable systems of equations by substitution

8.5

Solving 3 variable systems of equations by elimination

8.6

Solving 3 variable systems of equations with no or infinite solutions

8.7

Word problems relating 3 variable systems of equations