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Master Two-Step Linear Equations: Solve ax + b = c Easily

EQAO Grade 9 Math: Master Core Concepts & Skills

Ratios, Rates, and Proportions

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Ratios

Ratios - Find The Missing Value LHS

Ratios - Find The Missing Value RHS

Equivalent Ratios

Rates

Find the Biggest Rate 

Find the Unit Price 

Unit Rate Fill in Box

Find the Quickest Rate 

Unit Rate

Proportions

Proportions — Missing Denominator

Proportions — Missing Numerator

Proportions - Find the Missing Denominator LHS

Proportions - Find the Missing Denominator RHS

Proportions - Find the Missing Numerator LHS

Proportions - Find the Missing Numerator RHS

Square Roots

Squares and square roots

Square Root of a Perfect Square

Estimating square roots

Pythagorean Theorem

Introduction to pythagorean theorem

Using the pythagorean relationship

Applications of pythagorean theorem

Rational Numbers

Comparing and ordering rational numbers

Comparing decimal numbers

Comparing fractions

Solving problems with rational numbers in decimal form

Mixed Operations with Decimals

Mixed Operations

Mixed Operations with Decimals Bracket

Mixed Operations with Bracket Square

Solving problems with rational numbers in fraction form

Operations with fractions

Determine square roots of rational numbers

Square roots of rational numbers

Powers and Exponents

Using exponents to describe numbers

Expanded powers

Exponent rules

Single Power Expressions

Dividing powers

Multiplying powers

Order of operations with exponents

Using exponents to solve problems

Proportional Relationships

Understanding graphs of proportional relationships

Linear relations

Using tables of values to graph proportional relationships

Linear relation

Applications of proportional relationships

Identifying proportional relationships

Linear Ralations

Representing patterns in linear relations

Represent Patterns in Linear Relations Equation Decimal

Represent Patterns in Linear Relations Equation Integer Start From 0

Represent Patterns in Linear Relations Equation Integer Start From 1

Represent Patterns in Linear Relations Equation Negative Decimal

Identify the Linear Equation

Reading linear relation graphs

Solving linear equations by graphing

Solving Linear Equations

Solving linear equations using multiplication and division

Two-step Linear Equations LHS

Two-step Linear Equations RHS

Solving two-step linear equations: ax + b = c, x/a + b = c

Solving two-step linear equations: ax + b = c, x/a + b = c

Solving linear equations using distributive property: a(x + b) = c

Solving linear equations using distributive property: a(x + b) = c

Solving linear equations with variables on both sides

Introduction to Relations and Functions

Relationship between two variables

Understand relations between x- and y-intercepts

Domain and range of a function

Identifying functions

Function notation

Linear Functions

Distance formula: \(d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)

Distance formula: <katex>d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}</katex>

Distance formula

Midpoint formula: \(M = ( \frac{x_1+x_2}2  ,\frac{y_1+y_2}2)\)

Midpoint formula

Midpoint formula: <katex>M = ( \frac{x_1+x_2}2 ,\frac{y_1+y_2}2)</katex>

Midpoint formula: <katex>M = ( \frac{x_1+x_2}2 ,\frac{y_1+y_2}2)</katex>

Slope equation: \(m = \frac{y_2-y_1}{x_2- x_1}\)

Slope equation: <katex>m = \frac{y_2-y_1}{x_2- x_1}</katex>

Slope intercept form: y = mx + b

General form: Ax + By + C = 0

Point-slope form: \(y - y_1 = m (x - x_1)\)

Graphing linear functions using table of values

Graphing linear functions using x- and y-intercepts

Graphing from slope-intercept form y=mx+b

Graphing linear functions using a single point and slope

Word problems of graphing linear functions

Rate of change

Parallel and perpendicular lines in linear functions

Applications of linear relations

Introduction to Polynomials

Characteristics of polynomials

What are polynomials

Equivalent expressions of polynomials

Adding and subtracting polynomials

Multiplication and Division of Polynomials

Multiplying and dividing monomials 

Divide a monomial by a monomial

Multiply a monomial by a monomial

Multiplying polynomials by monomials

Multiply a polynomial by a monomial

Dividing polynomials by monomials

Introduction to 3-Dimensional Objects

Introduction to surface area of 3-dimensional shapes

Nets of 3-dimensional shapes

Surface area of prisms

Surface Area of Prisms Rectangle

Calculate the Surface Area

Surface area of cylinders

Surface Area and Volume

Surface area and volume of prisms

Surface area and volume of pyramids

Surface area and volume of cylinders

Surface area and volume of cones

Surface area and volume of spheres

Circle Geometry

Angles in a circle

Chord properties 

Tangent properties

Data Management

Influencing factors in data collection

Classification of data

Characteristics of Quantitative Data

Classify the Level of Measurement

Identify the Level of Measurement

Sampling methods

Sampling Methods

Scatter plots and correlation

Census and bias

Census and Bias

Classifying Bias

Linear Programming

What is linear programming?

Finding Optimal Values Given Constraints In Slope-Intercept Form

Finding Optimal Values Given Constraints In Standard Form

Linear programming word problems

EQAO Grade 9 Principles of Math

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Intro

- Hi, welcome to this question right here. Wow, this is the type of question where you don't just cross multiply right away. You have to remove something else before you can do the short cut. What happened is we've got a four over five plus five over 4x equals one over three. Now the idea is simple. You want to solve the x which is here. You have to remove anything that is furthest away from there first. The four over five has to go first. What we'll do is, we'll keep the five over 4x as it is. We're going to subtract the four over five from both sides. We're going to subtract the four over five from this side and from this side. Now it is still mathematically the same thing. If you subtract the four over five from here, that four over five is gone from the question. Then it's just one over three minus the four over five. What I'm going to recommend if you're going to show all your work then you will have to combine these two fractions together. Now when it comes to fractions, adding and subtracting, you have to keep the denominator the same. That's a three and that's a five so it doesn't work. You have to find the lowest common denominator between the three and the five. The lowest common denominator between the three and the five would be the 15. If you want to change the three to 15 you have to times it by five. You do the same to the bottom, you have to do the same to the top. Three times five is 15, and one times five is still the five. This one over here because you want to get to 15, right? 
Mathematically, you'll be thinking five times what gives me 15? Times three. If you times the three to the bottom then you will have to times it by three to the top as well. Three times four is 12. Let's write down the work in a different color so you can see what happened there. What happened here is we times this by a five, we times that by a five, we times that by a three, and we times that by a three. Right now, we've got a five minus 12 all over 15. If you want, I would recommend that you actually do it this way. Change the common denominator into one denominator. You can do that. Then the top is just five minus 12. So you won't do anything weird. You'll just keep the denominator the same but this time you'll just go five minus the 12 on the top, I think it's negative seven if I remember correctly. Yes, and that's negative seven over 15 so far. On the left hand side, the five over 4x is still waiting for you. I would recommend you write the x right beside the five. It makes it look a little bit nicer. We're trying to solve the x still. But this time if you look at your question now. It's five x over four equal to the negative seven over 15. Two fractions on either side of the equals sign. What can you do? 
Cross multiply. I will actually now take the cross multiply method. I will take the four and multiply it to the negative seven. Take the five and multiply it down to the 15. Why do I do that? I want to keep the x by itself on the top. Now the x is on the top by itself, it's alone but that's what we want. Take the four times the negative seven, it's negative 28. Take the five times the 15, that's too big for me, it's 75. Then we've got 28 over 75. Is is possible we can reduce this number? Let me get a quick calculation here. Nothing we can do. Final answer. Negative 28 over 75. Thanks for watching.

Solving two-step linear equations literally means solving the equations in two major steps. First, we need to isolate the unknown "x" to one side of the equation. You can then solve the "x". To complete these two steps, you may need to perform addition, subtraction, division, multiplication, cross multiplication, and so on. When the equation has fractions, you may also need to find the common denominator before proceeding further. Seems complicated? No worries! You will learn all the tricks in this section.

Solving two-step Linear equations: ax+b = c, x/a +b = c

How to solve two-step linear equations

Model and solve one-step linear equations: ax = b, x/a = b

Solving two-step linear equations using addition and subtraction: ax + b = c

Solving two-step linear equations using multiplication and division: x/a + b = c