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Practice questions for SohCahToa

Grade 11 Math: Master Advanced Concepts & Skills

11FA.A1.1

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Characteristics of quadratic functions

Applications of quadratic functions

11FA.A1.2

Quadratic function in general form: y = ax^2 + bx + c

Quadratic function in vertex form: y = a(x-p)^2 + q

Multiplying polynomial by polynomial

11FA.A1.3

Factor by taking out the greatest common factor

Factor by taking out GCF

Factor by grouping

Factoring difference of squares: \(x^2 - y^2\)

Factoring difference of squares: <katex>x^2 - y^2</katex>

Factoring difference of squares: x^2 - y^2

Factoring trinomials

Factoring Trinomials

11FA.A1.4

Solving quadratic equations by factoring

11FA.A1.5

Graphing quadratic functions: General form VS. Vertex form

Finding the quadratic functions for given parabolas

11FA.A1.6

Using quadratic formula to solve quadratic equations

Solving a quadratic equation with TWO REAL SOLUTIONS

Solving a quadratic equation with TWO COMPLEX SOLUTIONS

11FA.A1.7

Nature of roots of quadratic equations: The discriminant

11FA.A1.8

Solving quadratic equations by completing the square

Applications of quadratic equations

11FA.A2.1

Identifying functions

Function notation

11FA.A2.2

Function notation (advanced)

11FA.A2.3

Domain and range of a function

11FA.A2.4

Introduction to quadratic functions

11FA.A2.5

Transformations of quadratic functions

11FA.A2.6

Combining transformations of functions

11FA.A2.7

Converting from general to vertex form by completing the square

11FA.A2.8

Completing the square

Completing the Square

11FA.A2.9

Shortcut: Vertex formula

Converting general form into vertex form by applying the vertex formula

Vertex Formula Application

11FA.B1.1

Exponents: Rational exponents

Convert between radicals and rational exponents

11FA.B1.2

Exponents: Power rule: (a^x)^y = a^(xy)

Exponents: Power rule

Combining the exponent rules

11FA.B1.3

Graphing exponential functions

11FA.B1.4

Graphing transformations of exponential functions

11FA.B1.5

Finding an exponential function given its graph

11FA.B2.1

Exponential growth and decay by a factor

11FA.B2.2

Evaluating logarithms using change-of-base formula

Solving exponential equations using exponent rules

11FA.B3.1

Exponential growth and decay by percentage

11FA.B3.2

Exponential decay: Half-life

11FA.B3.3

Finance: Compound interest

Finance: Compound Interest

11FA.C1.1

Use sine ratio to calculate angles and sides (Sin = o / h)

Use cosine ratio to calculate angles and sides (Cos = a / h)

Use tangent ratio to calculate angles and sides (Tan = o / a)

11FA.C1.2

Combination of SohCahToa questions

11FA.C1.3

Law of sines

Ambiguous case: SSA triangles

Law of cosines

11FA.C1.4

Applications of the sine law and cosine law

11FA.C1.5

Introduction to bearings

Bearings and direction word problems

Bearings and Direction Word Problems

Angle of elevation and depression

11FA.C2.1

Sine graph: y = sin x

11FA.C2.2

Cosine graph: y = cos x

11FA.C2.3

Tangent graph: y = tan x

11FA.C2.4

Cotangent graph: y = cot x

11FA.C2.5

Secant graph: y = sec x

11FA.C2.6

Cosecant graph: y = csc x

11FA.C2.7

Graphing transformations of trigonometric functions

11FA.C3.1

Determining trigonometric functions given their graphs

11FA.C3.2

Ferris wheel trig problems

11FA.C3.3

Tides and water depth trig problems

Spring (simple harmonic motion) trig problems

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Grade 11 Functions and Applications, University/College Preparation (MCF3M)

A. Quadratic Functions

B. Exponential Functions

C. Trigonometric Functions

math

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Ex. 1

- Hi! Welcome to this question right here. So this one here you can use whatever you like. Sohcahtoa, you can use sin, cos, tangent as long as you can find the length from b to c, which is from here to here. Okay? 
So how do we know the length from there to there? We only know the angle over here is 22 and this angle here is 15. But if you look in a different way you can actually see there's one right triangle right here. So you can actually find the length from a to b because you kind of know this side's 80 and if you know this angle right here, maybe you can find the length a to b. Then if you look at a bigger scale, if I can just go ahead and treat this big triangle right here, because I know this whole thing right here is 22 plus 15, I can also figure out the a to c. Then I can take the a to c, subtract the a to b and I'll get the b to c. Okay? Kind of weird. Let's actually do it step by step. So let's actually find the length a to b first. So here is my length a to b. So here we go. To find the length a to b, you have to visualize your triangle as actually just this part right here. So you're trying to find the opposite side from this angle 22. This is the opposite, this is the adjacent. So you're going to use tangent. So for the length a to b, I will be using tangent of 22 degrees and the opposite will be the one I'm looking for which is the length a to b divided by the 80 degrees which is the adjacent which is over here. So I'm going to go ahead and calculate that. I've got tangent 22 times 80. Tangent 22 times 80. I'm just gonna write down 32.3. And let's call that centimeters for now. So what about a to c? If you're doing a to c, then you have to look at the triangle like this. Look at it like this. These two angles right here is just 22 plus 15. Twenty-two plus 15, we get 37, right. So from this angle you're looking for the opposite side and you have the adjacent 80 again. So it will just be tangent once again. Using the tangent 37, using these two triangles together is equal to the length of a to c divided by 80 again. So I'm going to go tangent 37 and I'm going to multiply it by 80. A little bit of cross multiplying. I get myself a 60.3 centimeters. So if I know from here to here it's 63 centimeters. So from here to here the blue line is 63 in total and the a to b over here is just 32 roughly, then what will be my b to c? 
Well, just subtract the difference and that's it, right? 
So it just goes 63.2 minus 32.2. . . are they all 0.3s? My bad. All 0.3s. So three and threes are gone. So 63.3-- oh, it's actually 60. I'm really sorry all those mistakes right here. So this is actually 60.3, okay. So, 60.3 minus 32.3 I get myself 28, okay. Sorry about all those scribbles. The final answer should be just 28 centimeters if that was centimeters. Okay? Thanks for watching!

Ex. 2

SOHCAHTOA is actually a memory aid to memorize how to calculate sine, cosine and <a href="[[glossary.html|{"keyword":"Tangent (in Trigonometry)"}]]">tangent</a> of an angle. SOH: sine = opposite over hypotenuse; CAH = adjacent over hypotenuse; and TOA = opposite over adjacent. Besides using them separately, the sine, cosine, and tangent ratios can be used together to solve trigonometry problems.

Use sine ratio to calculate angles and sides (Sin = \(  \frac{o}{h}\) )

Use cosine ratio to calculate angles and sides (Cos =  \(  \frac{a}{h}\)  )

Use tangent ratio to calculate angles and sides (Tan =  \(  \frac{o}{a}\)  )

ASTC rule in trigonometry (All Students Take Calculus)