Root test

Root test

In this section, we will look at a very useful limit question that will be used frequently when doing the root test. We will then learn and apply the root test to determine the convergence and divergence of series. Root test requires you to calculate the value of R using the formula below. If R is greater than 1, then the series is divergent. If R is less than 1, then the series is convergent. If R is equal to 1, then the test fails and you would have to use another test to show the convergence or divergence of the series. You may notice that this looks very similar to the ratio test. Also note that if the root test fails, then the ratio test will also fail. Thus, make sure to not waste time doing the ratio test if the root test fails.
Basic Concepts:Introduction to infinite series, Convergence and divergence of normal infinite series ,

Lessons

Note *Let ∑an\sum a_n be a positive series. Then we say that

R=R= lim⁡\limn →∞\infty ∣an∣1n\mid a_n\mid^{\frac{1}{n}}

Where:
1. If RR < 11, then the series is convergent (or absolutely convergent)
2. If RR > 11, then the series is divergent
3. If R=1R=1, then the series could either be divergent, or convergent

Basically if R=1R=1, then the root test fails and would require a different test to determine the convergence or divergence of the series.

Note that if the root test gives R=1R=1, then so will the ratio test.
  • Introduction
    Root Test Overview
  • 1.
    Useful Limit Question Used for Root test
    Show that lim⁡\limn →∞\infty n1n=1n^{\frac{1}{n}}=1. This fact is useful when doing the root test for infinite series.
  • 2.
    Convergence & Divergence of Root test
    Use the Root test to determine if the series converges or diverges. If the root test does not determine the convergence or divergence of the series, then resort to another test.
    a)
    ∑n=1∞(−3)n2n \sum_{n=1}^{\infty}\frac{(-3)^n}{2n}

    b)
    ∑n=0∞(n)2n+1π1−2n \sum_{n=0}^{\infty}\frac{(n)^{2n+1}}{\pi^{1-2n}}

    c)
    ∑n=1∞[n2−2n35+2n3]3n \sum_{n=1}^{\infty}[\frac{n^2-2n^3}{5+2n^3} ]^{3n}

    d)
    ∑n=1∞nn3n \sum_{n=1}^{\infty}\frac{n^n}{3^n}

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5.
Sequence and Series
5.1
Introduction to sequences
5.2
Monotonic and bounded sequences
5.3
Introduction to infinite series
5.4
Convergence and divergence of normal infinite series
5.5
Convergence & divergence of geometric series
5.6
Convergence & divergence of telescoping series
5.7
Divergence of harmonic series
5.8
P Series
5.9
Alternating series test
5.10
Divergence test
5.11
Comparison & limit comparison test
5.12
Integral test
5.13
Ratio test
5.14
Root test
5.15
Absolute & conditional convergence
5.16
Radius and interval of convergence with power series
5.17
Functions expressed as power series
5.18
Taylor series and Maclaurin series
5.19
Approximating functions with Taylor polynomials and error bounds
Integral Calculus
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