# Area of parametric equations

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##### Intros

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##### Examples

###### Lessons

**Finding the Area Given the Range of the Parameter**

Find the area under the curve of the parametric curve $x=t^2+1$ $y=t^3+t^2+4$, where $1 \leq t \leq 3$.

Assume that the curve traces perfectly from left to right for the range of the parameter $t$.- Find the area enclosed of the given parametric curve $x=a \cos (\theta)$, $y= b \sin (\theta)$, where $0 \leq \theta \leq 2 \pi$ and $a, b$ are constants.
- Find the area under the curve of the parametric equations $x=t-\frac{1}{t}$, $y=t+\frac{1}{t}$, where $\frac{1}{2} \leq t \leq 2$.

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###### Topic Notes

In this section, we will learn find the area under the curve of parametric equations. This still involves integration, but the integrand looks changed. The integrand is now the product between the second function and the derivative of the first function. We will examine the different types of parametric equations with a given range, and learn how to find the area of each one.

Normally we know that the area under the curve from $a$ to $b$ is $\int_{a}^{b} f(x)dx$. However, what about parametric equations?

Let the curve be defined by the parametric equations $x=f(t)$, $y=g(t)$ and let the value of $t$ be increasing from $\alpha$ to $\beta$. Then we say that the area under the parametric curve is:

$A = \int_{a}^{b} y \; dx=\int_{\alpha}^{\beta} g(t)f'(t)dt$

However, if the value of $t$ is increasing from $\beta$ to $\alpha$ instead, then the area under the parametric curve will be:

$A = \int_{a}^{b} y \; dx=\int_{\beta}^{\alpha} g(t)f'(t)dt$

Be careful when determining which one to use!

Let the curve be defined by the parametric equations $x=f(t)$, $y=g(t)$ and let the value of $t$ be increasing from $\alpha$ to $\beta$. Then we say that the area under the parametric curve is:

$A = \int_{a}^{b} y \; dx=\int_{\alpha}^{\beta} g(t)f'(t)dt$

However, if the value of $t$ is increasing from $\beta$ to $\alpha$ instead, then the area under the parametric curve will be:

$A = \int_{a}^{b} y \; dx=\int_{\beta}^{\alpha} g(t)f'(t)dt$

Be careful when determining which one to use!

###### Basic Concepts

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