Area of triangles:12ab\frac{1}{2} ab sinC - Trigonometric Ratios and Angle Measures

Area of triangles:12ab\frac{1}{2} ab sinC


In this lesson, we will learn:
  • Proof: Area of Triangle =12absinC\frac{1}{2}ab \sin C
  • Finding the Area of a Triangle Given 2 Sides and the Angle in Between
  • Area of Isosceles Triangles
  • Area of Equilateral Triangles
  • Determining the Areas of Different Triangles

  • The base and height of a triangle must be perpendicular to each other.
  • The traditional formula for the area of a triangle = 12×base×height\frac{1}{2} \times base \times height
  • An isosceles triangle has two sides of equal length.
  • An equilateral triangle has three sides of equal length and all the inner angles equal to 60°.
  • Angles inside a triangle add up to 180°.
  • Pythagorean Theorem: a2+b2=c2a^{2}+b^{2}=c^{2}
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Area of triangles:12ab\frac{1}{2} ab sinC

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