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Area of triangles: 1/2 a*b sin(C)

Now Playing:Area of triangles 1 2absinc– Example 0
Intros
  1. Introduction to Area of Triangles: 12absin⁡C\frac{1}{2} ab\sin C
Examples
  1. Proof: Area of Triangle = 12absin⁡C\frac{1}{2} ab\sin C

    Using the given diagram, prove that the area of a triangle can be found by the equation 12absin⁡C\frac{1}{2} ab\sin C

    MATH11 10 10 1
    Area of triangles: 1/2 a*b sin(C)
    Jump to:Notes
    Notes
    In this lesson, we will learn:
    • Proof: Area of Triangle =12absin⁡C\frac{1}{2}ab \sin C
    • Finding the Area of a Triangle Given 2 Sides and the Angle in Between
    • Area of Isosceles Triangles
    • Area of Equilateral Triangles
    • Determining the Areas of Different Triangles

    Notes:
    • The base and height of a triangle must be perpendicular to each other.
    • The traditional formula for the area of a triangle = 12×base×height\frac{1}{2} \times base \times height
    • An isosceles triangle has two sides of equal length.
    • An equilateral triangle has three sides of equal length and all the inner angles equal to 60°.
    • Angles inside a triangle add up to 180°.
    • Pythagorean Theorem: a2+b2=c2a^{2}+b^{2}=c^{2}