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Home
Geometry
Points, Lines, Segments, Midpoints and Chords

Graph using a single point and slope

Still Confused?

Try reviewing these fundamentals first

Algebra
Solving linear equations by graphing
Algebra
Slope intercept form: y = mx + b
Algebra
Slope-point form: $y - y_1 = m (x - x_1)$

Nope, got it.

That's it, no more lessons

Still Confused?

Nope, got it.

That's it, no more lessons

Still don't get it?

Nope, I got it.

Still don't get it?

Review these basic concepts…

Solving linear equations by graphing
Slope intercept form: y = mx + b
Slope-point form: $y - y_1 = m (x - x_1)$

Nope, I got it.

or

Start now and get better math marks!

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Start now and get better math marks!

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Chapter 3.5 Playlist

Lesson: 1a) - Graph the following line that passes through the given point and the slope

(-3, 2) ;

m =

{2 \over 3}

Intro
Learn
Practice

Do better in math today

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Chapter 3 Topics:

3.1
Midpoint formula: $M = ( \frac{x_1+x_2}2 ,\frac{y_1+y_2}2)$
3.2
Chord properties in circle geometry
3.3
Distance formula: $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$
3.4
Slope-Y-intercept form: y = mx + b
3.5
Graph using a single point and slope
3.6
Solve linear equations
Back to Course Index

Don't just watch, practice makes perfect.

Do better in math today

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Chapter 3 Topics:

3.1
Midpoint formula: $M = ( \frac{x_1+x_2}2 ,\frac{y_1+y_2}2)$
3.2
Chord properties in circle geometry
3.3
Distance formula: $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$
3.4
Slope-Y-intercept form: y = mx + b
3.5
Graph using a single point and slope
3.6
Solve linear equations
Back to Course Index

Don't just watch, practice makes perfect.

Graph using a single point and slope

If we are given a single point and the slope of a straight line, we will be able to graph it. By the same token, we can determine the slope and intercepts if we are given from its graph.

Basic concepts:
Solving linear equations by graphing
Slope intercept form: y = mx + b
Slope-point form: $y - y_1 = m (x - x_1)$

Related concepts:
Special case of linear equations: Horizontal lines
Special case of linear equations: Vertical lines
Parallel line equation
Perpendicular line equation

Lessons

1.
Graph the following line that passes through the given point and the slope
2.
Find the slope, x and y intercepts of each line.

Graph using a single point and slope

Don't just watch, practice makes perfect.

We have 429 practice questions in Geometry for you to work through.

Get Started Now

Graph using a single point and slope

Don't just watch, practice makes perfect.

We have over 420 practice questions in Geometry for you to master.

Get Started Now

Graphing linear functions using a single point and slope

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Try reviewing these fundamentals first

AlgebraSolving linear equations by graphing

AlgebraSlope intercept form: y = mx + b

AlgebraSlope-point form: y−y1=m(x−x1)y - y_1 = m (x - x_1)y−y​1​​=m(x−x​1​​)

Nope, got it.

Play next lesson

That's it, no more lessons

Practice this topic

Nope, got it.

Play next lesson

That's it, no more lessons

Goto next topic

Still don't get it?

Nope, I got it.

Still don't get it?

Review these basic concepts…

Solving linear equations by graphing

Slope intercept form: y = mx + b

Slope-point form: y−y1=m(x−x1)y - y_1 = m (x - x_1)y−y​1​​=m(x−x​1​​)

Nope, I got it.

Play next lesson or Practice this topic

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Start now and get better math marks!

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Lesson: 1a

Selected

Lesson: 1b

Lesson: 1c

Lesson: 1d

Lesson: 1e

Lesson: 1f

Lesson: 2a

Lesson: 2b

Lesson: 2c

Lesson: 2d

Intro

Learn

Practice

Do better in math today

Don't just watch, practice makes perfect.

Do better in math today

Don't just watch, practice makes perfect.

Lessons

1.

Graph the following line that passes through the given point and the slope

a)

(−3,2); (-3, 2) ; (−3,2);m =23 {2 \over 3}​3​​2​​

b)

(4,−2); (4, -2); (4,−2);m = -35 {3 \over 5} ​5​​3​​

c)

(1,2); (1, 2); (1,2);m = undefined

d)

(2,5); (2, 5); (2,5);m = 0

e)

x int = 2; m = -1

f)

y int = -3; m = 32 {3 \over 2}​2​​3​​

2.

Find the slope, x and y intercepts of each line.

a)

b)

c)

d)

Don't just watch, practice makes perfect.

Graph using a single point and slope

Don't just watch, practice makes perfect.

We have over 420 practice questions in Geometry for you to master.

Algebra
Solving linear equations by graphing

Algebra
Slope intercept form: y = mx + b

Algebra
Slope-point form: $y - y_1 = m (x - x_1)$

Slope-point form: $y - y_1 = m (x - x_1)$

or

$(-3, 2) ;$ m = ${2 \over 3}$

$(4, -2);$ m = - ${3 \over 5}$

$(1, 2);$ m = undefined

$(2, 5);$ m = 0

y int = -3; m = ${3 \over 2}$