# Pollution and hard water treatment by precipitation

#### Everything You Need in One Place

Homework problems? Exam preparation? Trying to grasp a concept or just brushing up the basics? Our extensive help & practice library have got you covered.

#### Learn and Practice With Ease

Our proven video lessons ease you through problems quickly, and you get tonnes of friendly practice on questions that trip students up on tests and finals.

#### Instant and Unlimited Help

Our personalized learning platform enables you to instantly find the exact walkthrough to your specific type of question. Activate unlimited help now!

##### Intros
###### Lessons
1. What is 'pollution' and hard water?
2. Using precipitation to clean water.
3. Worked calculation: Using Ksp and equilibrium to treat water.
4. Hard water.
##### Examples
###### Lessons
1. Use the Ksp expression to calculate concentrations of aqueous ions in treating water pollution.

A sample of industrial waste water has a Pb2+ concentration of 7.9*10-4 M, and 'acceptable levels' of lead ions in water have been stated as a maximum of 7.25*10-10 M.

What amount of OH- ions need to be added to precipitate lead ions, so that [Pb2+] drops to the acceptable level at most? The Ksp for Pb(OH)2 is 1.43*10-20 M.1
1. Use the Ksp expression to calculate concentrations of aqueous ions in treating water pollution.

A sample of industrial waste water has a Pb2+ concentration of 6.5*10-3 M, and 'acceptable levels' of lead ions in water have been stated as a maximum of 7.25*10-10 M.

What amount of CO32- ions need to be added to precipitate lead ions, so that [Pb2+] drops to the acceptable level at most? The Ksp for PbCO3 is 7.4*10-14 M.1

1 Reference for solubility constant data: http://www4.ncsu.edu/~franzen/public_html/CH201/data/Solubility_Product_Constants.pdf
###### Topic Notes

In this lesson, we will learn:

• How precipitation is used to treat water pollution and hard water.
• To recall the meaning of the terms suspension and supernatant.
• How to use Ksp and ion concentrations to solve problems related to hard water and pollution.

Notes:

• Being able to precipitate ions out of solution is very important in chemistry. Removing impurities or βtreatingβ a water sample is similar to cleaning a work space.
• Some dirt/stains are very light and donβt interfere with general working. Dust builds up but can be removed quickly too, so a general dry wipe across a surface is enough.
In chemistry, light metal ions such as Na+ or K+ are fairly safe in living environments. They are very soluble in water but are carried around quite easily too, and they do not build up to dangerous levels very often. Many living organisms actually need these lighter ions for living processes.
• On the other hand, some dirt/stains build up slowly but they are harder to remove and can make workspaces harder to use. Sometimes we need to use chemicals specifically designed to remove dirt.
Transition metal ions and heavy metal ions such as Pb2+ and Cd2+ have high mass, build up where they are produced and interfere with living processes. These properties make them harmful to living organisms in rivers or other aquatic environments.

• Although they are harmful, heavy metals can be precipitated out of solution. When we precipitate the harmful heavy metal ions, they are converted from the aqueous state (where they cause harm), to the solid state which can be trapped and filtered out of the solution. There are three stages we need to describe in this process:
• The solution, as we already know is when the ions are still dissolved.
• The suspension, where the aqueous ions have been precipitated but have not settled in the container/system.
• The precipitate, where the ions have settled at the bottom of the container. The remaining solution without the precipitate is called the supernatant.
Precipitating pollutant ions out of solution can be done using the principles from Predicting a precipitate and Solubility product.

• Worked example:

A sample of waste water has a Pb2+ concentration of 5*10-4 M, and βsafe levelsβ of lead ions in water can be said to be a maximum of 7.25*10-8 M.

What amount of OH- ions need to be added to precipitate lead ions, so that [Pb2+] drops to the safe level at most? The Ksp for Pb(OH)2 is 1.43*10-20 M.1

First, write the equilibrium that will occur.

Pb(OH)2 (s) $\, \rightleftharpoons \enspace$Pb2+(aq) + 2OH-(aq)

Now write the Ksp expression for this using the value above:

Ksp = 1.43 * 10-20 = [Pb2+][OH-]2

[OH-]2 = $\large \frac{1.43 * 10^{-20}}{7.25 * 10^{-8}}$ = 1.97 * 10-13 M

[OH-] = $\sqrt{1.97 * 10^{-13}}$ = 4.44 * 10-7 M

The calculation above is finding the hydroxide ion concentration that causes the equilibrium with Pb(OH)2 (s) to be established, so if [Pb2+] greater than the 7.25*10-8 M safe level was reached, the equilibrium would simply shift to make more precipitate.

• Treating hard water involves precipitation as well. Hard water is caused by calcium (Ca2+) and magnesium (Mg2+) ions dissolved in water when limestone (CaCO3) and MgCO3 in the ground reacts with rain water (which is slightly acidic) and gets into the water supply.

CaCo3 (s) $\enspace \rightleftharpoons \enspace$ Ca2+(aq) + CO2 (g) + H2O(l)

Hard water has consequences in daily life:
• It gives drinking water a bad smell/taste.
• The dissolved ions can precipitate in piping and other places where it is heated, which can reduce the flow of pipes and make some appliances less useful.Β
• It makes soap less effective because the active ingredient in soap forms a precipitate with the Ca2+ and Mg2+ ions instead of cleaning the dirt you are using the soap to clean!

• Hard water is treated by using Na2CO3. This will precipitate CaCO3 again by the original equilibrium. Both CaCO3 and MgCO3 have low solubility.
• Permanent hard water is when the water does not contain any HCO3-$\,$ so it must be added.
• Temporary hard water already contains HCO3- $\,$ so heating the water can remove hardness.