Molarity  Solution Chemistry
Molarity
Lessons
Notes:
In this lesson, we will learn:
 The definition of molarity and how to describe it.
 An equation to calculate the concentration of ions in solution.
 An equation to find the change in concentration of a substance in solution.
Notes:
 We now have an understanding of what a solution is and what a solution does to chemical properties when substances are dissolved. These depend on the molarity of substances in solution.
 Molarity measures the number of moles of a substance per unit volume. It is how concentration is measured for chemical substances in solution – it asks “how much stuff in how much space?” for a chemical substance.
 The units of molarity are moles per liter (written mol/L or mol L^{1}), or mol per cubic decimeter (mol/dm^{3} or mol/dm^{3}). Both of these are equivalent and are often just given the symbol M.
 Calculating molarity is done by dividing the number of moles by the volume in liters according to the equation:
$Molarity$ $(mol L^{1}) =$ ${mol}\over{volume (L)}$
 When answering problems related to molarity, volume is often given in mL in chemical reactions – you’ll need to convert from mL to L if you are finding concentration of a solution! This is done by dividing by 1000 (or use the unit conversion method; 1 L = 1000 mL).
 In some problems you may be told the mass of the substance used (mass measured in grams). In this case you need to convert from mass to moles by finding molar mass of the substance. You can then use the unit conversion method to get the number of moles of the substance.
 Remember, concentration is always measured with respect to 1 L of substance, so M can always be written as mol over liters, for example:
$0.6 M = 0.6$ $mol L^{1} =$ ${0.6 mol} \over {1L}$
 The molarity equation lets chemists compare the concentration of two different solutions which may have different quantities – solutions with high molarity are called concentrated solutions, while low molarity solutions are called dilute solutions.
 Dilution is when more solvent is added to a solution. This has the effect of increasing the volume of the solution, therefore decreasing molarity (see the molarity equation!). This would be like adding water to a juice drink; the same number of ‘juice particles’ are spread amongst more water than before so the drink is less concentrated.
 Similarly, removing some solvent, by evaporating it for example, will decrease the volume of your solution and lead to a higher molarity. This would be concentrating your solution; the same amount of ‘juice particles’ in less water.
 Calculating concentration is also very important for many chemical reactions. Knowing the concentration of solutions, for example acids and alkali, enables chemists to use appropriate amounts of the reactants in experiments. When writing concentration of chemical substances, square brackets [ ] are used.
 For example [HCl] = 0.2 M tells chemists that a solution of hydrochloric acid has a concentration of 0.2 mol per liter.
 Molarity concentrations will often be used to find concentration of ions in solution that react in rather than the formal chemical compounds. This is for two reasons:
 It is the ions that actually cause the chemical properties and processes in solution to happen.
 Many ionic compounds dissociate into more than just two oppositely charged ions! For example every molecule of phosphoric acid H_{3}PO_{4} dissociates in solution into three H^{+} ions, the particle which actually take part in acidbase reactions. You need to multiply the concentration of the compound by the number of specific ions the compound produces to take this into account.
 For example: A solution of 0.4 M phosphoric acid, H_{3}PO_{4}, is made. As the formula shows, three H atoms are present in each molecule. Therefore in solution each single molecule will dissociate to form three H^{+} ions, so to find H^{+} concentration as multiply the concentration by three to find 0.4 * 3 = 1.2 M [H^{+}].
 There is an equation that relates the volume and concentration before and after a dilution has taken place. This equation allows you to measure change in concentration of a solution, whether solvent or another solution is added or removed:
$M_iV_i$ $=$ $M_fV_f$
Where:
M_{i} = initial molarity or concentration
M_{f} = final molarity or concentration
V_{i} = initial volume or concentration
V_{f} = final volume or concentration
 Calculating molarity is done by dividing the number of moles by the volume in liters according to the equation:
 When answering problems related to molarity, volume is often given in mL in chemical reactions – you’ll need to convert from mL to L if you are finding concentration of a solution! This is done by dividing by 1000 (or use the unit conversion method; 1 L = 1000 mL).
 In some problems you may be told the mass of the substance used (mass measured in grams). In this case you need to convert from mass to moles by finding molar mass of the substance. You can then use the unit conversion method to get the number of moles of the substance.
 Remember, concentration is always measured with respect to 1 L of substance, so M can always be written as mol over liters, for example:
 Dilution is when more solvent is added to a solution. This has the effect of increasing the volume of the solution, therefore decreasing molarity (see the molarity equation!). This would be like adding water to a juice drink; the same number of ‘juice particles’ are spread amongst more water than before so the drink is less concentrated.
 Similarly, removing some solvent, by evaporating it for example, will decrease the volume of your solution and lead to a higher molarity. This would be concentrating your solution; the same amount of ‘juice particles’ in less water.
 For example [HCl] = 0.2 M tells chemists that a solution of hydrochloric acid has a concentration of 0.2 mol per liter.
 It is the ions that actually cause the chemical properties and processes in solution to happen.
 Many ionic compounds dissociate into more than just two oppositely charged ions! For example every molecule of phosphoric acid H_{3}PO_{4} dissociates in solution into three H^{+} ions, the particle which actually take part in acidbase reactions. You need to multiply the concentration of the compound by the number of specific ions the compound produces to take this into account.
 For example: A solution of 0.4 M phosphoric acid, H_{3}PO_{4}, is made. As the formula shows, three H atoms are present in each molecule. Therefore in solution each single molecule will dissociate to form three H^{+} ions, so to find H^{+} concentration as multiply the concentration by three to find 0.4 * 3 = 1.2 M [H^{+}].
M_{i} = initial molarity or concentration
M_{f} = final molarity or concentration
V_{i} = initial volume or concentration
V_{f} = final volume or concentration

Intro Lesson
Molarity and concentration

1.
Apply the formula to find the concentration of solutions.

2.
Apply the formula to find changing concentration and volume of solutions.