1. Home
  2. >Calculus 3
  3. >Multiple Integrals
Help

Triple integrals in cylindrical coordinates

Everything You Need in One Place

Homework problems? Exam preparation? Trying to grasp a concept or just brushing up the basics? Our extensive help & practice library have got you covered.

Learn and Practice With Ease

Our proven video lessons ease you through problems quickly, and you get tonnes of friendly practice on questions that trip students up on tests and finals.

Instant and Unlimited Help

Our personalized learning platform enables you to instantly find the exact walkthrough to your specific type of question. Activate unlimited help now!

0/2
?
Intros
Lessons
  1. Triple Integrals in Cylindrical Coordinates Overview:
  2. Triple Integrals in Cylindrical Coordinates
    • Polar Coordinates →\to Cylindrical Coordinates
    • All xx's & yy's change to rr's & θ\theta
    • zz stays the same
  3. An Example of Converting to Cylindrical Coordinates
    • All xx's & yy's change to rr's & θ\theta
    • The variable zz stays the same
    • Add an extra rr
    • Integrate
0/4
?
Examples
Lessons
  1. Converting to Cylindrical Coordinates
    Convert the following triple integral to cylindrical coordinates

    ∫−20∫04−x2∫2x2+2y2−4x+y9−x2−y2 dz dy dx\large \int_{-2}^{0}\int_{0}^{\sqrt{4 - x^{2}}} \int_{2x^{2} + 2y^{2}-4}^{x+ y} \sqrt{9 - x^{2} - y^{2}}\, dz \,dy\, dx
    1. Convert the following triple integral to cylindrical coordinates

      ∫−33∫−9−y29−y2∫3z−52 zIn(x2+y2) dx dz dy\large \int_{-3}^{3}\int_{-\sqrt{9 - y^{2}}}^{\sqrt{9 - y^{2}}} \int_{3z- 5}^{2} \, zIn(x^{2} + y^{2})\, dx \,dz\, dy
      1. Converting & Integrating
        Evaluate  ∫∫∫E2dV  \, \int\int\int_{E} 2dV \, where  E  \, E \, is the region bounded by  z=x2+y2−2 \, z = x^{2} + y^{2} - 2 \, and  z=6−x2−y2 \, z = 6 - x^{2} - y^{2} .
        1. Evaluate  ∫∫∫E1dV  \, \int\int\int_{E} 1dV \, where  E  \, E \, is the region bounded by  z=4,z=x−y−3 \, z = 4, z = x - y - 3 \, and inside  x2+y2=4 \, x^{2} + y^{2} = 4 .
          Topic Notes
          ?
          Notes:

          Recall that when converting from Cartesian Coordinates to Polar Coordinates with double integrals we do the following:

          ∫∫Df(x,y)dA=∫θ=αθ=β∫r=g1(θ)r=g2(θ)f(rcos⁡θ,rsin⁡θ)rdrdθ\int \int_D f(x,y)dA = \int^{\theta=\beta}_{\theta=\alpha} \int^{r=g_2(\theta)}_{r=g_1(\theta)} f(r \cos \theta, r \sin \theta ) r dr d\theta

          With triple integrals, it is very similar. Instead of calling it polar coordinates, we call it cylindrical coordinates.

          Suppose we want to triple integrate f(x,y,z)f(x,y,z) in cylindrical coordinates in the following region of EE.

          α≤θ≤β \alpha \leq \theta \leq \beta
          g1(θ)≤r≤g2(θ) g_1 (\theta) \leq r \leq g_2 (\theta)
          h1(rcos⁡θ,rsin⁡θ)≤z≤h2(rcos⁡θ,rsin⁡θ)h_1 (r \cos \theta, r \sin \theta) \leq z \leq h_2(r \cos \theta, r \sin \theta)

          Then

          ∫∫∫Ef(x,y,z)dV=∫αβ∫g1(θ)g2(θ)∫h1(rcos⁡θ,rsin⁡θ)h2(rcos⁡θ,rsin⁡θ)f(rcos⁡θ,rsin⁡θ,z)rdzdrdθ \int \int \int_E f(x,y,z) dV = \int^{\beta}_{\alpha} \int^{g_2(\theta )}_{g_1(\theta )} \int^{h_2 (r \cos \theta, r \sin \theta)}_{h_1 (r \cos \theta, r \sin \theta)} f(r \cos \theta, r \sin \theta, z) rdzdrd\theta