Double integrals in polar coordinates

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Intros
Lessons
  1. Double Integrals in Polar Coordinates Overview:
  2. Review of Polar Coordinates
    • change all xx's and yy's into rr's and θ\theta's
    • x=rcosθ x = r \cos \theta
    • y=rsinθ y = r \sin \theta
    • An Example
  3. Double Integrals in Polar Coordinates
    • Convert to rr's and θ\theta's
    • Add an extra rr
    • Integrate in terms of rr & θ\theta
    • An Example
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Examples
Lessons
  1. Evaluating Double Integrals Using Polar Coordinates
    Evaluate the double integral D9x2+9y2dA\int \int_{D} \sqrt{9x^{2} + 9y^{2}} \, dA where the region DD is between the first quadrant of x2+y2=1 \, x^{2} + y^{2} = 1 \, and x2+y2=4 \, x^{2} + y^{2} = 4 .
    1. Evaluate the double integral DxydA\int \int_{D} x - y \, dA \, where the region DD is the portion of x2+y2=4 \, x^{2} + y^{2} = 4 \, in the second quadrant.
      1. Evaluate the following double integral

        2204x2ex2+y2dydx \large \int_{-2}^{2}\int_{0}^{\sqrt{4 - x^{2}}} \sqrt{e^{x^{2}+y^{2}}} \, dydx
        1. Use double integrals to determine the area of the region that is inside r=3+3sinθ \, r = 3 + 3 \, sin\theta\, and outside r=1sinθ \, r = 1 - \, sin\theta.
          Topic Notes
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          Notes:

          Review of Polar Coordinates

          When converting from Cartesian Coordinates to Polar Coordinates, we say that:

          x=rcosθ x = r \cos \theta
          y=rsinθy = r \sin \theta

          We change all xx's and yy's into rr's and θ\theta's. We also use these formulas that could be useful for conversions:

          x2+y2=r2x^2 + y^2 = r^2
          x2+y2=r\sqrt{x^2 + y^2} = r
          θ=tan1yx \theta = \tan^{-1} \frac{y}{x}

          Keep in mind that polar coordinates are useful when we come across circles or ellipses.


          Double Integrals in Polar Coordinates

          Suppose we have the following integral with region DD:

          Df(x,y)dA\int \int_D f(x,y)dA

          Then we can convert it into polar coordinates such that:

          Df(x,y)dA=θ=αθ=βr=g1(θ)r=g2(θ)f(rcosθ,rsinθ)rdrdθ\int \int_D f(x,y)dA = \int^{\theta= \beta }_{\theta = \alpha} \int^{r=g_2(\theta )}_{r=g_1(\theta )} f(r \cos \theta, r \sin \theta ) rdrd\theta

          Why do we have to convert to polar coordinates? Watch the video and find out!