# Surface area with double integrals

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**Finding the Surface Area with Double Integrals**

Determine the surface area of the surface $\, x + 2y + 2z = 4$ that is in the 1^{st}octant.- Determine the surface area of the surface $\, z = 2 - x^{2} - y^{2}$ that is above $z = 1 + x^{2} + y^{2}$ with $x \geq 0$ and $y \geq 0$.
- Determine the surface area of the surface $\, y = 3x^{2} + 3z^{2} - 4$ that is inside the cylinder $x^{2} + z^{2} =1$.

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