Example 19 - Chapter 10 Class 11 Straight Lines (Term 1)
Last updated at May 29, 2018 by Teachoo
Last updated at May 29, 2018 by Teachoo
Transcript
Example 19 Find the distance between the parallel lines 3x 4y + 7 = 0 and 3x 4y + 5 = 0 We know that , distance between two parallel lines Ax + By + C1 = 0 & Ax + By + C2 = 0 is d = | _1 _2 |/ ( ^2 + ^2 ) Distance between the parallel lines 3x 4y + 7 = 0 & 3x 4y + 5 = 0 is d = | _1 _2 |/ ( ^2 + ^2 ) Putting values d = |7 5|/ ((3)^2 + ( 4)^2 ) d = |2|/ (9 + 16) d = 2/ 25 d = 2/ (5 5) d = 2/5 Thus, the required distance is 2/5 units
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