Exponents: Division rule: a^x / a^y = a^(x-y)

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prove: ${8^5 \over 8^2} = 8^{5-2} = 8^3$ $\frac{8 ^{5}}{8 ^{2}} = 8^{5 - 2} = 8^{3}$
simplify: ${100a^{16}b^3c^7 \over 2a^4c^8}$ $\frac{100 a ^{16} b ^{3} c ^{7}}{2 a ^{4} c ^{8}}$

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Exponents: Division rule: a^x / a^y = a^(x-y)

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Exponents: Division rule: a^x / a^y = a^(x-y)

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