Still Confused?

Try reviewing these fundamentals first

- Home
- ACCUPLACER Test Prep
- Conics

Still Confused?

Try reviewing these fundamentals first

Still Confused?

Try reviewing these fundamentals first

Nope, got it.

That's the last lesson

Start now and get better math marks!

Get Started NowStart now and get better math marks!

Get Started NowStart now and get better math marks!

Get Started NowStart now and get better math marks!

Get Started Now- Lesson: 115:44
- Lesson: 220:25
- Lesson: 3a14:51
- Lesson: 3b9:14
- Lesson: 4a21:28
- Lesson: 4b13:19
- Lesson: 4c12:39

Basic Concepts: Quadratic function in vertex form: y = $a(x-p)^2 + q$, Converting from general to vertex form by completing the square, Shortcut: Vertex formula, Graphing parabolas for given quadratic functions

$p = \frac{1}{{4a}}$

- 1.
**vertical parabola VS. horizontal parabola**

Sketch the following vertical parabolas:

i) $y = {x^2}$

ii) $y = 2{x^2}$

iii) $y = 2{\left( {x + 3} \right)^2} + 1$ - 2.Sketch the following horizontal parabolas:

i) $x = {y^2}$

ii) $x = \frac{1}{2}{y^2}$

iii) $x = \frac{1}{2}{\left( {y - 1} \right)^2} - 3$ - 3.
**converting quadratic functions to vertex form by "completing the square"**

Convert each quadratic function from general form to vertex form by completing the square.a)$y = 2{x^2} - 12x + 10$b)${y^2} - 10y - 4x + 13 = 0$ - 4.
**finding the focus and directrix using the formula: $p = \frac{1}{{4a}}$**For each quadratic function, state the:

i) vertex

ii) axis of symmetry

iii) focus

iv) directrix

a)$y = \frac{1}{8}{\left( {x - 6} \right)^2} + 3$b)$- 12\left( {x + 1} \right) = {\left( {y + 4} \right)^2}$c)${y^2} - 10y - 4x + 13 = 0$

We have over 2320 practice questions in ACCUPLACER Test Prep for you to master.

Get Started Now