# Work and Energy

## Everything You Need in One PlaceHomework problems? Exam preparation? Trying to grasp a concept or just brushing up the basics? Our extensive help & practice library have got you covered. | ## Learn and Practice With EaseOur proven video lessons ease you through problems quickly, and you get tonnes of friendly practice on questions that trip students up on tests and finals. | ## Instant and Unlimited HelpOur personalized learning platform enables you to instantly find the exact walkthrough to your specific type of question. Activate unlimited help now! |

#### Make math click 🤔 and get better grades! 💯Join for Free

Get the most by viewing this topic in your current grade. __Pick your course now__.

##### Examples

###### Lessons

- $\bold{W = \Delta E_{mech} = F_\parallel d:}$
**Calculating work**- A 1170 kg car travels at 11.0 m/s.

- How much work needs to be done on the car to accelerate it to 24.0 m/s?
- What is the net force acting on the car that accelerates it, if the acceleration is uniform and happens over 95.0 m?

- A 5.50 kg box slides across a floor at 12.0 m/s. Friction slows the box to 2.00 m/s after is has travelled 13.0 m. Find the work done on the box and the force of friction acting on the box.
- A 2.50 kg box is initially at rest at the top of a 30.0° slope and reaches a speed of 11.5 m/s when it slides 12.0 m down the slope. Find the force of friction acting on the box.

- A 1170 kg car travels at 11.0 m/s.
- $\bold{W = \Delta E_{mech} = F_\parallel d:}$
**Calculating work with force applied at an angle**

A force of 885 N pulls on a box at an angle of 28.0° above the horizontal. 115 N of friction acts on the box as it slides 19.0 m. How much work does the 885 N force do on the box?