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Voltage divider method

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Voltage Divider Method

A clear walkthrough of the voltage divider method: how two series resistors split a source voltage, the formula derived from Ohm's law, worked examples, and when loading effects change the result.

What Is a Voltage Divider?

A voltage divider is one of the most common building blocks in circuit analysis. It takes a single source voltage and splits it into a smaller voltage across part of a circuit, using nothing more than two resistors connected in series. Because it appears everywhere from sensor circuits to volume controls, understanding the voltage divider method gives you a fast way to predict voltages without redrawing the whole circuit every time.

The idea relies on two facts you already know from Ohm’s law: the same current flows through every element in a series path, and the voltage dropped across any single resistor depends on its resistance relative to the total.

The Basic Circuit

Picture a source voltage \( V_{in} \) connected across two resistors, \( R_1 \) and \( R_2 \), wired one after the other. The output voltage \( V_{out} \) is measured across \( R_2 \), taken from the junction between the two resistors and the bottom rail.

Vin R1 Vout R2
Figure 1: A basic voltage divider — source \( V_{in} \) across \( R_1 \) and \( R_2 \) in series, with \( V_{out} \) taken across \( R_2 \).

Deriving the Voltage Divider Formula

Because \( R_1 \) and \( R_2 \) are in series, the same current \( I \) flows through both. Ohm’s law gives the total current from the source as:

\( I = \dfrac{V_{in}}{R_1+R_2} \)

The voltage across \( R_2 \) is simply that current multiplied by \( R_2 \):

\( V_{out} = I R_2 = \dfrac{V_{in}}{R_1+R_2} \cdot R_2 \)

which simplifies to the voltage divider formula:

\( V_{out} = V_{in} \cdot \dfrac{R_2}{R_1+R_2} \)

If you instead need the voltage across \( R_1 \), the same logic gives \( V_{R_1} = V_{in} \cdot \dfrac{R_1}{R_1+R_2} \). Notice the two output voltages always add back up to \( V_{in} \), since the resistors share the total voltage between them.

Worked Example

Suppose \( V_{in} = 12 \) volts, \( R_1 = 100 \) ohms, and \( R_2 \) can be adjusted. Using the formula:

\( V_{out} = 12 \cdot \dfrac{R_2}{100+R_2} \)

When \( R_2 = 100 \) ohms (equal to \( R_1 \)), the output is exactly half the source: \( V_{out} = 6 \) volts. As \( R_2 \) grows much larger than \( R_1 \), the fraction approaches 1 and \( V_{out} \) approaches the full 12 volts. As \( R_2 \) shrinks toward zero, \( V_{out} \) shrinks toward zero as well. The graph below shows this relationship.

Graph of output voltage V_out = 12 times R2 divided by (100 plus R2), as R2 varies Plot of y = 12*x/(100+x) for x in [0, 500] 0 100 200 300 400 500 0 2 4 6 8 10 R2 (ohms) Vout (volts) R2 = R1 gives half of Vin

Loading Effects: A Practical Caution

The divider formula assumes nothing else draws current from the output node. In practice, connecting a load resistor across \( V_{out} \) puts that load in parallel with \( R_2 \), lowering the effective resistance at that point and pulling the output voltage down from the value the formula predicts. This is the same idea behind the difference between open-circuit and loaded readings discussed in terminal voltage. For accurate designs, choose \( R_1 \) and \( R_2 \) much smaller than the load resistance, or accept the small deviation and account for it directly.

Voltage Divider vs. Current Divider

A voltage divider splits voltage across resistors in series; a current divider splits current across resistors in parallel. The two methods are mirror images of each other, both built from the same series and parallel resistance rules, but they answer different questions, so it helps to keep them as separate tools rather than one formula.

Key Takeaways

The voltage divider method turns a two-resistor series circuit into a quick calculation: multiply the source voltage by the fraction of total resistance carried by the resistor you care about. It rests entirely on Ohm’s law and the fact that series elements share the same current, and it becomes especially useful once you start comparing power dissipation and efficiency across different resistor choices in power efficiency problems.

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