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Get Started Now- Lesson: 1a8:29
- Lesson: 1b8:24

In this lesson, we will learn:
__Notes:__

or equivalently, by substituting Coulomb's law:

$|E| = k \frac{|Q|}{r^2}$

$E:$ electric field, in newtons per coulomb (N/C)

$F_e:$ electric force, in newtons (N)

$q:$ charge that experiences the field, in coulombs (C)

$k:$ Coulomb's law constant, $9.00 \times 10^9 N\centerdot m^2 / C^2$

$|Q|:$ magnitude of charge that creates the field, in coulombs (C)

$r:$ distance from charge, in meters (m)

$|F_e|:$ magnitude of electric force, in newtons (N)

$k:$ Coulomb's law constant, $9.00 \times 10^9 N\centerdot m^2 / C^2$

$|Q_1|, |Q_2|:$ magnitude of each charge, in coulombs (C)

$r:$ distance between charges, in meters (m)

- Meaning of electric field and its relationship to electric force
- How to draw electric field line diagrams
- Solving problems with electric field

__Electric field (__is the electric force exerted by a charge*E*)*Q*on another charge*q*, per unit charge of*q*. It is a vector quantity.- By convention, the direction of electric field vectors is defined as the direction that a positive test charge would move if placed in the field.
*F*points in the same direction as_{e}*E*for positive charges, and in the opposite direction of*E*for negative charges. - A test charge is a point charge with a very small magnitude. Test charges have a small magnitude charge so that the electric field of the test charge is negligible and does not affect the electric field that is being investigated.

**Electric Field**

or equivalently, by substituting Coulomb's law:

$|E| = k \frac{|Q|}{r^2}$

$E:$ electric field, in newtons per coulomb (N/C)

$F_e:$ electric force, in newtons (N)

$q:$ charge that experiences the field, in coulombs (C)

$k:$ Coulomb's law constant, $9.00 \times 10^9 N\centerdot m^2 / C^2$

$|Q|:$ magnitude of charge that creates the field, in coulombs (C)

$r:$ distance from charge, in meters (m)

**Coulomb's Law (Electric Force) **

$|F_e|:$ magnitude of electric force, in newtons (N)

$k:$ Coulomb's law constant, $9.00 \times 10^9 N\centerdot m^2 / C^2$

$|Q_1|, |Q_2|:$ magnitude of each charge, in coulombs (C)

$r:$ distance between charges, in meters (m)

- 1.
**Calculations with electric field**

A pair of positive and negative point charges are fixed in the following positions:

a)Find the electric field (magnitude and direction) at point A.b)A charge placed at A experiences a force of $5.9 \times 10^{-3} N$ [right]. Find the magnitude and polarity of the charge.