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# Finding an exponential function given its graph

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## What Are Exponential Functions?

Before we get into dealing with exponential functions and graphing exponential functions, letβs first take a look at the general formula and theory behind exponential functions.

Below is one of the most general forms of an exponential graph:

The exponential function equation to this graph is $y=2^x$, and is the most simple exponential graph we can make. If youβre wondering what $y=1^x$ would look like, hereβs its exponential graph:

Now, as to the reason why the graphs of $y=2^x$ and $y=1^x$ are so different, the best way to understand the theory behind exponential functions is to take a look at some tables.

Above you can see three tables for three different βbase valuesβ β 1, 2 and 3 β all of which are to the power of x. As you can see, for exponential functions with a βbase valueβ of 1, the value of y stays constant at 1, because 1 to the power of anything is just 1. That is why the above graph of $y=1^x$ is just a straight line. In the case of $y=2^x$ and $y=3^x$ (not pictured), on the other hand, we see an increasingly steepening curve for our graph. That is because as x increases, the value of y increases to a bigger and bigger value each time, or what we call βexponentiallyβ.

Now that we have an idea of what exponential equations look like in a graph, letβs give the general formula for exponential functions:

$y=ab^{d(x-c)}+k$

The above formula is a little more complicated than previous functions youβve likely worked with, so letβs define all of the variables.

y β the value on the y-axis

a β the vertical stretch or compression factor

b β the base value

x β the value on the x-axis

c β the horizontal translation factor

d β the horizontal stretch or compression factor

k β the vertical translation factor

In this lesson, weβll only be going over very basic exponential functions, so you donβt need to worry about some of the above variables. But, so you have access to all of the information you need about exponential functions and how to graph exponential functions, letβs outline what changing each of these variables does to the graph of an exponential equation.

**1) Variable "a"**

Letβs compare the graph of $y=2^x$ to another exponential equation where we modify βaβ, giving us $y=(-4)2^x$

By making this transformation, we have both βstretchedβ and βreflectedβ the original graph of $y=2^x$ by itβs y-values. In order to find βaβ by looking at the graph, the most important thing to notice is that when x=0 and we donβt have a value for βkβ, the y-intercept of our graph is always going to be equal to βaβ.

**2) Variable βbβ**

Also known as the βbase valueβ this is simply the number that has the exponent attached to it. Finding it involves algebra, which will be discussed later in this article.

**Variable βcβ**

Letβs compare the graph of $y=2^x$ to another exponential equation where we modify βcβ, giving us $y=2^{(x-2)}$

By making this transformation, we have shifted the entire graph to the **right** two units. If βcβ was equal to -2, we would have shifted the entire graph to the **left** two units.

**Variable βdβ**

Letβs compare the graph of $y=2^x$ to another exponential equation where we modify βdβ, giving us $y=2^{4x}$

By making this transformation, we have stretched the original graph of $y=2^x$ by its **x-values**, similar to how the variable βaβ modifies the function by its **y-values**. If βdβ were negative in this example, the exponential function would undergo a horizontal reflection as opposed to the vertical reflection seen with βaβ.

**Variable βkβ**

Letβs compare the graph of $y=2^x$ to another exponential equation where we modify βkβ, giving us $y=2^x+2$

By making this transformation, we have translated the original graph of $y=2^x$ up two units. If βkβ were negative in this example, the exponential function would have been translated down two units. βkβ is a particularly important variable, as it is also equal to what we call the horizontal asymptote! An asymptote is a value for either x or y that a function approaches, but never actually equals.

Take for example the function $y=2^x$: for this exponential function, k=0, and therefore the βhorizontal asymptoteβ equals 0. This makes sense, because no matter what value we put in for x, we will never get y to equal 0. For our other function $y=2^x+2$, k=2, and therefore the horizontal asymptote equals 2. There is no value for x we can use to make y=2.

And thatβs all of the variables! Again, several of these are more complicated than others, so it will take time to get used to working with them all and becoming comfortable finding them. To get a better look at exponential functions, and to become familiar with the above general equation, visit this excellent graphing calculator website here. Take your time to play around with the variables, and get a better feel for how changing each of the variables effects the nature of the function.

Now, letβs get down to business. Given an exponential function graph, how can we find the exponential equation?

## How To Find Exponential Functions

Finding the equation of exponential functions is often a multi-step process, and every problem is different based upon the information and type of graph we are given. Given the graph of exponential functions, we need to be able to take some information from the graph itself, and then solve for the stuff we are unable to take directly from the graph. Below is a list of all of the variables we may have to look for, and how to usually find them:

a β solve for it using algebra, or it will be given

b β solve for it using algebra, or it will be given

c β let x = 0 and imagine βcβ is not there, the value of y will equal the y-intercept; now count how many units the y value for the y-intercept is from the y-axis, and this will equal βcβ

d β solve for it using algebra

k β equal to the value of the horizontal asymptote

Of course, these are just the general steps you need to take in order to find the exponential function equation. The best way to learn how to do this is to try some practice problems!

**Exponential Functions Examples:**

Now letβs try a couple examples in order to put all of the theory weβve covered into practice. With practice, youβll be able to find exponential functions with ease!

**Example 1:**

Determine the exponential function in the form $y=ab^x$ of the given graph.

In order to solve this problem, weβre going to need to find the variables βaβ and βbβ. As well, weβre going to have to solve both of these algebraically, as we canβt determine them from the exponential function graph itself.

**Step 1: Solve for βaβ**

To solve for βaβ, we must pick a point on the graph where we can eliminate bx because we donβt yet know βbβ, and therefore we should pick the y-intercept (0,3). Since b0 equals 1, we can find that a=3. As a shortcut, since we donβtβ have a value for k, a is just equal to the y-intercept of this equation.

**Step 2: Solve for βbβ**

Now that we have βaβ, all we have to do is sub in 3 for βaβ, pick another point, and solve for b. Letβs pick the point (1,6). With all this information, we can find that b=2.

**Step 3: Write the Final Equation**

Now we that we have found all of the necessary variables, all thatβs left is to write out our final equation in the form $y=ab^x$. Our final answer is $y=(3)2^x$

**Example 2:**

Determine the exponential function in the form $y=a2^{dx}+k$ of the given graph.

In order to solve this problem, weβre going to need to find the variables βaβ, βdβ and βkβ. Remember, we can find βkβ from the graph, as it is the horizontal asymptote. For βaβ and βdβ, however, weβre going to have to solve for these algebraically, as we canβt determine them from the exponential function graph itself.

**Step 1: Find βkβ from the Graph**

To find βkβ, all we need to do is find the horizontal asymptote, which is clearly y=6. Therefore, k=6.

**Step 2: Solve for βaβ**

To solve for βaβ, just like the last example, we must pick a point on the graph where we can eliminate 2dx because we donβt yet know βdβ, and therefore we should pick the y-intercept (0,3). Since 20 equals 1, subbing (0, 3) into $y=a2^{dx}+6$ gives us that a=-3.

**Step 3: Solve for βbβ**

Now that we have βaβ and βkβ, all we have to do is pick another point and solve for b. Letβs pick the point (0.25, 0). With all this information, we can find that d=4.

**Step 4: Write the Final Equation**

Now we that we have found all of the necessary variables, all thatβs left is to write out our final equation in the form $y=ab^{dx}+k$. Our final answer is $y=(-3)2^{4x}+6$

And thatβs it for exponential functions! Again, these functions are a little more complex than equations for lines or parabolas, so be sure to do lots of practice problems to get a hang of the new variables and techniques. With more practice, soon exponential equations and the graphs of exponential functions will be no trouble at all!

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### Finding an exponential function given its graph

#### Lessons

- 1.Determine an exponential function in the form $y=a \cdot b^x$ with the given graph.

- 2.Determine an exponential function in the form ${y = 3^{x-h} + k }$ with y-intercept 5 and asymptote ${y = -4.}$
- 3.Determine an exponential function in the form $y=a \cdot 2^{bx}+k$ with the given graph.