Graphing linear functions using a single point and slope - Linear Functions

Graphing linear functions using a single point and slope

If we are given a single point and the slope of a straight line, we will be able to graph it. By the same token, we can determine the slope and intercepts if we are given from its graph.

Basic Concepts
Solving linear equations by graphing
Slope intercept form: y = mx + b
Point-slope form: $y - y_1 = m (x - x_1)$

Related Concepts
Special case of linear equations: Horizontal lines
Special case of linear equations: Vertical lines
Parallel line equation
Perpendicular line equation

Lessons

1.
Graph the following line that passes through the given point and the slope
2.
Find the slope, x and y intercepts of each line.

Graphing linear functions using a single point and slope

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AlgebraSolving linear equations by graphing

AlgebraSlope intercept form: y = mx + b

AlgebraPoint-slope form: y−y1=m(x−x1)y - y_1 = m (x - x_1)y−y1​=m(x−x1​)

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Solving linear equations by graphing

Slope intercept form: y = mx + b

Point-slope form: y−y1=m(x−x1)y - y_1 = m (x - x_1)y−y1​=m(x−x1​)

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Lesson: 1a

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Lesson: 1b

Lesson: 1c

Lesson: 1d

Lesson: 1e

Lesson: 1f

Lesson: 2a

Lesson: 2b

Lesson: 2c

Lesson: 2d

Intro

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Practice

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Don't just watch, practice makes perfect

Do better in math today

Don't just watch, practice makes perfect

Lessons

1.

Graph the following line that passes through the given point and the slope

a)

(−3,2); (-3, 2) ; (−3,2);m =23 {2 \over 3}32​

b)

(4,−2); (4, -2); (4,−2);m = -35 {3 \over 5} 53​

c)

(1,2); (1, 2); (1,2);m = undefined

d)

(2,5); (2, 5); (2,5);m = 0

e)

x int = 2; m = -1

f)

y int = -3; m = 32 {3 \over 2}23​

2.

Find the slope, x and y intercepts of each line.

a)

b)

c)

d)

Graphing linear functions using a single point and slope

Don't just watch, practice makes perfect.

We have over 1850 practice questions in Algebra for you to master.

Algebra
Solving linear equations by graphing

Algebra
Slope intercept form: y = mx + b

Algebra
Point-slope form: $y - y_1 = m (x - x_1)$

Point-slope form: $y - y_1 = m (x - x_1)$

or

$(-3, 2) ;$ m = ${2 \over 3}$

$(4, -2);$ m = - ${3 \over 5}$

$(1, 2);$ m = undefined

$(2, 5);$ m = 0

y int = -3; m = ${3 \over 2}$